Answer:
(6,-1)
Solve for the first varible in one of the equations, then subsititue the other equation.
Answer:
(xy - 4)(xy + 4).
Step-by-step explanation:
The is the difference of 2 squares.
a^2 - b^2 = (a - b)(a + b: so we have:
x^2y^2 - 16 = (xy - 4)(xy + 4)
You need to look at the x values when you calculate that.
There is a line which goes from -2 to 0. Another line at 0 to 4 and the last line is 7 to infinity.
You can combine the first two and get B) (-2, 4] and [7, infinity)
Answer:
Huh?? I have no idea what you said.
Step-by-step explanation:
