Answer:
Seven
Step-by-step explanation:
Let G7, G8, and G9 be the numbers of students in the respective grades.
Then, G7 + G8 + G9 = LCM of G8 and G9
<em>Data:
</em>
G8 = 5
G9 = 3
<em>Calculations:
</em>
<em>Multiples of 5</em>: 1 2 10 15
<em>Multiples of 3</em>: 1 3 6 9 15
The <em>LCM</em> of 5 and 3 is 15.
G7 + 5 + 3 = 15 Combine like terms
G7 + 8 = 15 Subtract 8 from each side
G7 = 7
There are seven students in Grade 7.
Answer:
Given that rotating 90 degrees clockwise around the origin switches the x andy values and makes the new y value negative, we can, for example, switch (2, 1) to (1, -2). 180 degrees clockwise simply makes both values negative (-2, -1), and 270 degrees clockwise switches them and makes the new y value negative (-1, 2), we can plug those in to our JM endpoints to turn (-5, 1) into (-1, -5) and (-6, 2) into (-2, -6)
Step-by-step explanation:
1) Take the perimeter and divide it by 4.
2) Take the answer from step 1 and square it (multiply by itself)
Answer:
Step-by-step explanation:
<u>Given Data:</u>
Base area = 
= 108 in.²
Volume = V = 729 in.³
<u>Required:</u>
Height = h = ?
<u>Formula:</u>
<u>Solution:</u>
For h, rearranging formula:
![\displaystyle h = \frac{V}{A_{B}} \\\\h =\frac{729 \ in.^3}{108 \ in.^2} \\\\h = 6.75 \ in.\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20h%20%3D%20%5Cfrac%7BV%7D%7BA_%7BB%7D%7D%20%5C%5C%5C%5Ch%20%3D%5Cfrac%7B729%20%5C%20in.%5E3%7D%7B108%20%5C%20in.%5E2%7D%20%5C%5C%5C%5Ch%20%3D%206.75%20%5C%20in.%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
