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3 years ago

What is the range and domain of y=1-x

2 answers:

8 0

I would recommend using a app on google for this it will give you the right answer on Brainly most of the time they give you the wrong answers

pav-90 [236]3 years ago

6 0

Answer:

Step-by-step explanation:

what is the range and domain

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-4 + 8 - 5

pochemuha

Answer:

-1

Step-by-step explanation:

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1 year ago

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Helpppppp:((((((this is due tomorrow and I still didn’t turn it in. Pls help if you can and take ur time but pls don’t take too

Arlecino [84]

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3 years ago

Heyyyyyy I need someone to help me

Bess [88]

Answer:2 op

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3 years ago

Solve the linear system of equations <br> 8x−4y=20 5x−8y=62 <br> x= <br> y=

LUCKY_DIMON [66]

Answer:

x = -2

x = -9

Step-by-step explanation:

The linear system is:

8x - 4y = 20 ⇒ (1)

5x - 8y = 62 ⇒ (2)

To solve the system multiply equation (1) by -2 to make the coefficients of y equal in values and different in signs, then add the resulting equation with equation (2)

∵ -2(8x) + -2(-4y) = -2(20)

∴ -16x + 8y = -40 ⇒ (3)

- Add equation (2) and (3)

∴ -11x = 22

- Divide both sides by -11

∴ x = -2

Substitute the value of x in equation (1) or (2)

∵ 8(-2) - 4y = 20

∴ -16 - 4y = 20

- Add 16 to both sides

∴ - 4y = 36

- Divide both sides by -4

∴ y = -9

3 0

3 years ago

Show all work below to answer the following for a certain city that had a population of 150,000 in the year 2010. In 2020, the p

Gelneren [198K]

The constant rate of continuous growth, k, for this population is equal to 2.11935%. And the population will reach 250,000 people in 24.36 years.

For solving this question, you should apply the Population Growth Equation.

<h3>Population Growth Equation</h3>

The formula for the Population Growth Equation is:

$P_f=P_o*(1+\frac{R}{100} )^t$

Pf= future population

Po=initial population

r=growth rate

t= time (years)

STEP 1 - Find the constant rate of continuous growth, k, for this population.

For this exercise, you have:

Pf= future population= 185,000 in 2020.

Po=initial population =150,000 in 2010.

r=growth rate= ?

t= time (years)=2020-2010=10

Then,

$P_f=P_o*(1+\frac{R}{100} )^t\\ \\ 185000=150000\cdot \left(1+\frac{R}{100}\:\right)^{10}\\ \\ \left(1+\frac{R}{100}\right)^{10}=\frac{185000}{150000} \\ \\ \left(1+\frac{R}{100}\right)^{10}=\frac{37}{30}\\ \\ R=100\sqrt[10]{\frac{37}{30}}-100=2.11935\%$

STEP 2 - Find the <em>t</em> for population 250,000 people.

$P_f=P_o*(1+\frac{R}{100} )^t\\ \\ 250000=150000\cdot \left(1+\frac{2.11935}{100}\:\right)^{10}\\ \\ \left(1+\frac{2.11935}{100}\right)^{10}=\frac{250000}{150000} \\ \\ \left(1+\frac{2.11935}{100}\right)^t=\frac{5}{3}\\ \\ t\ln \left(1+\frac{2.11935}{100}\right)=\ln \left(\frac{5}{3}\right)\\ \\ t=\frac{\ln \left(\frac{5}{3}\right)}{\ln \left(\frac{102.11935}{100}\right)}\\ \\ t=24.36$

Read more about the population growth equation here:

brainly.com/question/25630111

7 0

2 years ago