Answer:
25000 fragments
Explanation:
A restriction enzyme can cut a random DNA sequence once per every 4^n where n = number of bases in the recognition site of enzyme.
There are 6 bases in Xbal's recognition site (TCTAGA) so it will cut once per every 4^6 = 4096 bases (4kb).
Total genomic size = 100000kb
So expected number of fragments = Total genomic size/Size of one fragment
= 100000/4
= 25000 fragments
Answer:
is bound to the constant region of the secondary antibody.
Explanation:
Enzyme immunoassays are the techniques used to detect the presence of antigens with the help of antibodies. Each of the antibody molecules has a constant and variable region.
The primary antibodies are added to the wells. The constant region of the secondary antibody is bound to an enzyme while its variable region is free so that it can bind to the specific antigen.
Addition of substrate to the system is followed by visualization and/or evaluation of antigen as the reaction between enzyme and substrate produce some visible changes such as color change.
In the grassland trees and shrubs are rarely anywhere compared to the temperate forest. The animals don’t have a lot of shelter in the grasslands compared to the temperate forests.
Both a b c are the right answer choice for this question
