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sergiy2304 [10]
2 years ago
11

Which statements describe the graph of 2 and StartFraction 8 over 9 EndFraction greater-than-or-equal-to x on a number line? Sel

ect three options.
Mathematics
1 answer:
Liula [17]2 years ago
8 0
WILLOW TREE GREEN TEA FROM THE PARK AND BELL PARK
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The perimeter of a rectangle must be less than 156 feet. If the length is known to be 66 feet, find the range of possible widths
balu736 [363]

x = perimeter

x<156

length = 66

so, in order to calculate perimeter you need to add two lengths and two widths

so

156 (perimeter) - 2 (66) = two widths

156 - 132 = 24 (remember this number is two widths added together)

so 24 twice the width SO 12 would be the number that the width can't be larger than

the width has to be less than 12

w < 12

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3 years ago
My hw says, "suppose E has a coordinate of -1 And EG= 7" what is the possible coordinate of G?​
evablogger [386]

Answer:

-8,6

Step-by-step explanation:

from what i can tell this is a 1D problem. |E-G|=7, and E=-1, so -1-G=+-7. G=-8 or 6

7 0
3 years ago
Read 2 more answers
write a polynomial function of least degree with integral coefficients that has the given zeros. -(1/3), -i
inessss [21]

Answer:

f(x)=3x^3+x^2+3x+1

Step-by-step explanation:

If a real number -\frac{1}{3} is a zero of polynomial function, then

x-\left(-\dfrac{1}{3}\right)=x+\dfrac{1}{3}

is the factor of this function.

If a complex number -i is a xero of the polynomial function, then the complex number i is also a zero of this function and

x-(-i)=x+i\ \text{ and }\ x-i

are two factors of this function.

So, the function of least degree is

f(x)=\left(x+\dfrac{1}{3}\right)(x+i)(x-i)=\left(x+\dfrac{1}{3}\right)(x^2-i^2)=\\ \\ =\left(x+\dfrac{1}{3}\right)(x^2+1)=\dfrac{1}{3}(3x+1)(x^2+1)=\dfrac{1}{3}(3x^3+x^2+3x+1)

If the polynomial function must be with integer coefficients, then it has a form

f(x)=3x^3+x^2+3x+1

4 0
3 years ago
Can help me with: <br>cosx/senx cotx =1​
Stolb23 [73]
I assume the question was true or false. Here is how you verify the identity— which is true :)

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3 years ago
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