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Vlad [161]
3 years ago
9

Round 452,906 to the nearest ten thousand

Mathematics
2 answers:
ruslelena [56]3 years ago
7 0
450000 is the answer, if you have trouble rounding again go to the website everydaycalculation.com
tatuchka [14]3 years ago
6 0

460,000       or if you want it to the nearest hundred thousand it would be 500,000

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A store had a vending machine. Customers put in a quarter, and they receive a handful of candy.The machine is profitable if x &g
a_sh-v [17]

Answer:

Step-by-step explanation:

try to use mathwy to get your answer but ima say c d e and i think b but i really dont know about b

x has to be a bigger number than forty because the allitgator eating the bigger number which is x so that mean x is a bigger number than 40.

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4 years ago
Read 2 more answers
O Rs 600
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7 0
3 years ago
PLEASE HELP 20 POINTS PLEASE GIVE EXPLANTION ​
Georgia [21]

Answer:

300 in³

Step-by-step explanation:

To calculate the volume of a composite solid, simply split it into smaller solids and calculate their separate volumes. The volumes of each of the individual solids are then added together to give the total volume of the composite solid.

Remember, the formula for volume is: l • w • h

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7 0
2 years ago
Heathers rabbit has a mass of 5.190 kilograms.Jeff's rabbits has a mass of 5.195 kilograms.Write an inequality statement compari
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6 0
4 years ago
What initial investment must be made to accumulate $60000 in 17 years if the money is invested in a mutual fund that pays 12% an
mars1129 [50]

$7881.18

Step-by-step explanation:

   Let the initial Investment be P_{0}. The Interest is compounded on a monthly basis at 12% annual interest rate. After 17 years, the Investment amounts to $60,000.

   As the annual interest rate is 12%, the monthly interest rate is 1%.

Since this is a compound interest problem, the total amount can be modeled as follows: P(t)=P_{0}(1+\frac{i}{100})^{t}

Here i is the interest rate, i.e 1, and t is the number of time periods, i.e 17\textrm{ years x }12\frac{\textrm{months}}{\textrm{year}}= 204\textrm{ months}

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P_{0}=7881.18

∴ Initial Investment = $7881.18

4 0
3 years ago
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