It would be 50 an acute angle is always under 50 atleast
Answer:
<em>n = 0</em>
Step-by-step explanation:
- 6(n - 3) = 18
n - 3 = 18 ÷ ( - 6)
n - 3 = - 3 ⇒ <em>n = 0</em>
Answer:
Both answers should be -2 and 14.
Step-by-step explanation:
Using the quadratic formula:
Therefore:
The object's maximum height is the same as the y-coordinate of the vertex.To find that, first, finds the x- coordinate(t).You can find it by:
first identifying a,b and c.Multiply the b by negative 1 or simply change its sign and divide it by 2a.Afterward, plug the answer in the equation to find y, your answer.
(ax+bx²+c=-16t²+64t+80). Therefore, a=-6, b= 64 and c=80
-64/2(-16)=-64/-32=2
-16(2)²+64(2)+80=144 ft
So the maximum height of the object, when launched 64ft/sec from a platform that is 80 ft high, is 144 ft
Hope this helps(there are other methods)
Answer:
4 and 2 thirds or 4 2/3 <mixed number
Step-by-step explanation:
4+10=14
14/3n=4.666 repeating decimal or just 4 2/3
