3 years ago

Write the equation of a line with a slope of 5 and a y-intercept of (0, 3). Write the equation in slope-intercept form.

Mathematics

1 answer:

sladkih [1.3K]3 years ago

7 0

The answer is y=-5x+3

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Use the table to work out the values of

Pachacha [2.7K]

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Step-by-step explanation:

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4 years ago

Select ALL the values from the set {4, 4.5, 6.5, 9}

Andreas93 [3]

Answer:

7.09

Step-by-step explanation:

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Matt had 60 questions correct on a Percent’s Chapter Test that had 150 one-mark questions. What was his mark written as a percen

mel-nik [20]

Answer:

His mark, as a percentage, was of 40%.

Step-by-step explanation:

Mark as a percentage:

His mark as a percentage is the number of questions correct multiplied by 100% and divided by the number of questions.

In this problem:

60 questions correct out of 150. So

60*100%/150 = 40%

His mark, as a percentage, was of 40%.

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3 years ago

Which equations represent the asymptotes of the hyperbola (x-1)^2/36-(y-2)^2/64=1 ?

allochka39001 [22]

Answer:

$4x+3y=10$ and $4x-3y=-2$

Step-by-step explanation:

The asymptote equation of a translate hyperbola with equation $\frac{(x-h)^2}{b^2}-\frac{(y-k)^2}{a^2}=1$ is $y=\pm\frac{b}{a}(x-h)+k$

The given hyperbola has equation: $\frac{(x-1)^2}{36}-\frac{(y-2)^2}{64}=1$

Or $\frac{(x-1)^2}{6^2}-\frac{(y-2)^2}{8^2}=1$

Comparing to $\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

We have a=6 and b=8, h=1 and k=2.

We substitute this values to get:

$y=\pm\frac{6}{8}(x-1)+2$

$y=\pm\frac{4}{3}(x-1)+2$

$3y=\pm4(x-1)+6$

We split the plus or minus sign to get:

$3y=4x-4+6$

$3y=4x+2$

$3y-4x=2$

$3y=-4(x-1)+6$

$3y=-4x+4+6$

$3y+4x=10$

5 0

4 years ago

Translate: 4 less than a number<br><br> A.) 4>n<br> B.) n-4<br> C.) 4-n

Rzqust [24]

Answer:

b. n-4

Step-by-step explanation:

a number=n

4 less than it =n-4

8 0

4 years ago