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Tpy6a [65]
1 year ago
15

A = 8, b = 4, and c = 16

Mathematics
2 answers:
horsena [70]1 year ago
5 0
<h3>Answer: \sf 3\dfrac{4}{31} \quad or \quad \dfrac{97}{31}</h3>

-------------------------------------------------------------------------------------------------------

The given expression:

\sf \dfrac{2b + 3c^2}{4a^2 - 2b}

Here given <u>a = 8</u>, <u>b = 4</u>, and <u>c = 16</u>

<u />

Inserting this values

\sf \dfrac{2(4) + 3(16)^2}{4(8)^2 - 2(4)}

Simplify following

\sf \dfrac{8 + 3(256)}{4(64) - 8}

Distribute inside parenthesis

\sf \dfrac{8 + 768}{256 - 8}

Add/Subtract similar terms

\sf \dfrac{776}{248}

Simplify following, in improper fraction

\sf \dfrac{97}{31}

In mixed fraction, answer:

\sf 3\dfrac{4}{31}

Vsevolod [243]1 year ago
4 0

Answer:

3 \frac{4}{31}

Step-by-step explanation:

\frac{2(4) + 3(16) {}^{2} }{4(8) {}^{2} - 2(4) }

\frac{776}{248}

3 \frac{4}{31}

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