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1 year ago

A = 8, b = 4, and c = 16

Mathematics

2 answers:

horsena [70]1 year ago

5 0

<h3>Answer: $\sf 3\dfrac{4}{31} \quad or \quad \dfrac{97}{31}$ </h3>

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The given expression:

$\sf \dfrac{2b + 3c^2}{4a^2 - 2b}$

Here given <u>a = 8</u>, <u>b = 4</u>, and <u>c = 16</u>

<u />

Inserting this values

$\sf \dfrac{2(4) + 3(16)^2}{4(8)^2 - 2(4)}$

Simplify following

$\sf \dfrac{8 + 3(256)}{4(64) - 8}$

Distribute inside parenthesis

$\sf \dfrac{8 + 768}{256 - 8}$

Add/Subtract similar terms

$\sf \dfrac{776}{248}$

Simplify following, in improper fraction

$\sf \dfrac{97}{31}$

In mixed fraction, answer:

$\sf 3\dfrac{4}{31}$

Vsevolod [243]1 year ago

4 0

Answer:

$3 \frac{4}{31}$

Step-by-step explanation:

$\frac{2(4) + 3(16) {}^{2} }{4(8) {}^{2} - 2(4) }$

$\frac{776}{248}$

$3 \frac{4}{31}$

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Answer:

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