What is the area of the triangle on top? Include units. Base = 6 Length.1 = 6 Length.2 = 3

Mathematics

2 answers:

iogann1982 [59]2 years ago

8 0

I agree. the answer is 54

disa [49]2 years ago

6 0

54

Multiply 6 × 6 × 3 and then divide that by 2

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Please help 10 points and I will be ur friend I need help with Geometry bad

sineoko [7]

Ok, let's use N and N'.
N is (-1,-1). N' is (4,6).
From point N, the quadrilateral moves to the right 5 and up 7.
So, N+(5,7)=N'.

3 0

3 years ago

What is the price of the items Nakita bought?

timurjin [86]

Answer:

B $10.45

Step-by-step explanation:

Fist you find how much the 2 boxes of cracker cost

$3.50 * 2 = $7

Then subtract the amount of 2 crackers by the $0.80 coupon

$7 - $0.80 = $6.20

Then add that amount to the cost of a jar of peanut butter

$6.20 + $4.85 = $11.05

Then add that about for with the amount of a package of juice boxes

$11.05 + $2.40 = $13.45

Then subtract the total amount to the $3.00 coupon

$13.45 - $3.00 = $10.45

B $10.45 is your answer

4 0

3 years ago

Simplify the square root of 3 times the fifth root of 3.

bogdanovich [222]

Answer:

<h2><em>Three to the three fifths power.</em></h2>

Step-by-step explanation:

The given expression is

$\sqrt{3\sqrt[5]{3} }$

To simplify this expression, we have to use a specific power property which allow us to transform a root into a power with a fractional exponent, the property states:

$\sqrt[n]{x^{m}}=x^{\frac{m}{n}}$

Applying the property, we have:

$\sqrt{3\sqrt[5]{3}}=\sqrt{3(3)^{\frac{1}{5}}}=(3(3)^{\frac{1}{5}})^{\frac{1}{2}}$

Now, we multiply exponents:

$(3(3)^{\frac{1}{5}})^{\frac{1}{2}}\\3^{\frac{1}{2}}3^{\frac{1}{10}}$

Then, we sum exponents to get the simplest form:

$3^{\frac{1}{2}}3^{\frac{1}{10}}=3^{\frac{1}{2}+\frac{1}{10}} =3^{\frac{10+2}{20}}=3^{\frac{12}{20}} \\\therefore \sqrt{3\sqrt[5]{3}}=3^{\frac{3}{5} }$