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1 year ago

What is the area of the triangle on top? Include units. Base = 6 Length.1 = 6 Length.2 = 3

Mathematics

2 answers:

iogann1982 [59]1 year ago

8 0

I agree. the answer is 54

disa [49]1 year ago

6 0

54

Multiply 6 × 6 × 3 and then divide that by 2

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There are 12 boys and 16 girls in one class. Is the ratio remains the same for the whole school, How many more girls than boys a

IRINA_888 [86]

The answer is that there would be 500 girls in the school

7 0

3 years ago

Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week. A sample of

Aleks [24]

Answer:

CI for 90% = ( 16.34, 18.66)

Therefore at 90% confidence interval (a,b) = ( 16.34, 18.66)

And,

CI for 95% = ( 16.11, 18.89)

Therefore at 95% confidence interval (a,b) = ( 16.11, 18.89)

Step-by-step explanation:

Answer: = ( 2.64, 3.14)

Therefore at 95% confidence interval (a,b) = ( 2.64, 3.14)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 17.5

Standard deviation r = 5.7

Number of samples n = 65

Confidence interval = 90% and 95%

z(at 90% confidence) = 1.645

z(at 95% confidence) = 1.96

Substituting the values we have; for 90%

17.5+/-1.645(5.7/√65)

17.5+/-1.645(0.707)

17.5 +/- 1.16

= ( 16.34, 18.66)

Therefore at 90% confidence interval (a,b) = ( 16.34, 18.66)

Substituting the values we have; for 95%

17.5+/-1.96(5.7/√65)

17.5+/-1.96(0.707)

17.5 +/- 1.39

= ( 16.11, 18.89)

Therefore at 95% confidence interval (a,b) = ( 16.11, 18.89)

3 0

3 years ago

A group of freshmen at a local university consider joining the equestrian team. Thirty‑five percent of students choose Western r

lesantik [10]

Answer:

a) Option D) 0.75

b) Option D) 0.3

Step-by-step explanation:

We are given the following in the question:

Percentage of students who choose Western riding = 35%

$P(w) = 0.35$

Percentage of students who choose dressage= 45%

$P(d) = 0.45$

Percentage of students who choose jumping = 50%

$P(j) = 0.50$

Percentage of students who choose both dressage and jumping = 20%

$P(d \cap j) = 0.20$

Percentage of students who choose Western and dressage = 10%

$P(w \cap d) = 0.10$

Percentage of students who choose Western and jumping = 0%

$P(w \cap j) = 0$

Thus, we can say

$P(w \cap j \cap d) = 0$

Formula:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

a) P(student chooses dressage or jumping)

$P(d \cup j) = P(d) + P(j) -p(d \cap j)\\= 0.45 + 0.50-0.20 = 0.75$

b) P(student chooses neither dressage nor Western riding)

$= 1 - P(d \cup w)\\= 1 - (P(d) + P(w) - P(d \cap w))\\= 1 - (0.45 + 0.35 - 0.10)= 0.3$

5 0

3 years ago

Find the interest in dollars and the proceeds for the following problem. Choose the right answers. John Green received a $580 di

joja [24]

The interest
580×0.16×(60÷360)
=15.47
The proceeds
580−15.47
=564.53

5 0

3 years ago

Read 2 more answers

Please check screenshot

nata0808 [166]

Answer:

im sorry but whats the question exactly i will try to awnser it

Step-by-step explanation

6 0

3 years ago