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2 years ago

Find the slope and the y-intercept of the equation y − 3(x − 1) = 0.

1 answer:

3 0

Y-(3x-1)=0
y-3x+1=0
y=3x-1
The equation is in the form y=mx+q where m is the slope and q is the y-intercept.
Then the slope of that line is 3 and y-intercept is -1

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Which system of equations is graphed below?

algol [13]

(Pls give brainliest! :D)

Answer:

B

Step-by-step explanation:

You know that the graph intercepts at the point of (4,-2)

Where x = 4 and y = -2.

This means that whenever you plug a value of x in the equation it should give the value of y.

For example when you plug x= 4 into the equation (B), it should look like this.

4- y = 6, solving for y gives us the value negative 2.

This means that it does give us this point, however, as the graph shows us, both lines meet at the point which means that both equation should give us this point.

If we substitute x = 4 in the second equation of b, we should be able to get 3(4) + 4y = 4. Solving for y gives us -2.

Hope this helps!

-Yumi

4 0

2 years ago

Read 2 more answers

Please help me no one even bothers to help so plzzzz i BEGGGGGGGGGGG

user100 [1]

Answer:

Here's what I get.

Step-by-step explanation:

When you dilate an object by a scale factor, you multiply its coordinates by the same number.

If the scale factor is 4, the rule is (x, y) ⟶ (4x, 4y)

Your table then becomes

$\begin{array}{lcl}\textbf{Vertices of}& \, & \textbf{Vertices of}\\\textbf{VWXY}& \, & \textbf{V'W'X'Y'}\\V(-1 ,1) & \quad & V'(-4, 4)\\W(-1, 2) & \quad & W'(-4, 8)\\X(2, -1) & \quad & X'(8 ,-4)\\Y(2, 2) & \quad & Y'(8, 8)\\\end{array}$

The diagram below shows figure VVXY as a green bow-tie and its image V'W'X'Y' in orange.

The scale factor is greater than one, so the dilation is an enlargement.

7 0

2 years ago

Juan says that 8, 1 3/4, and -12 are all integers. Is he correct? Explain your answer. Please help me fast

monitta

No, he is not right.

Integer is a number that can be written without a fractional component, and 1 3/4 doesn't.

Here's an image for you to better understand.

8 0

3 years ago

Read 2 more answers

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

b. Find the marginal joint density of $X$ and $Y$ by integrating the joint density with respect to $z$ :

$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

7 0

2 years ago

Como converter 13 graus em radianos?

victus00 [196]

Answer:

13 grados es igual a 0.226893 radianes

Step-by-step explanation:

8 0

2 years ago