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3 years ago

What is the value of a?-2(a-8)+6a=36

1 answer:

8 0

$-2(a-8)+6a=36 \\ \\ -2a + 16 + 6a = 36 \\ \\ 4a + 16 = 36 \\ \\ 4a = 36 - 16 \\ \\ 4a = 20 \\ \\ a = \frac{20}{4} \\ \\ a = 5 \\ \\$

The final result is: a = 5.

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PLEASE HELP FAST 30 POINTS PLUS BRAINLIST ONLY ANSWER IF YOU KNOW

Katen [24]

ANSWER: 2327.04

EXPLANATION:

I’m assuming this is Reverse Pythagorean Theorem, so the equation would be c^2 - a^2 = b^2, so all you have to do it substitute the variables and solve. The length of the cable is variable c, the height of the tower is variable a, and the length of where is the cable is anchored and the base of the tower is variable b. That might not make any sense but feel free to ask any questions. :)

7 0

3 years ago

The sum of the first three terms in a GP is 38.Their product is 1728.Find the values of the three terms.

dusya [7]

Answer:

The value of the three terms is 8 and 18

Step-by-step explanation:

Let "a" be the first term and "r" be the common ratio.

Then from the condition, we have these two equations

a + ar + ar^2 = 38, (1)

a*(ar*)*(ar^2) = 1728. (2)

From equation (2), a^3*r^3 = 1728, or (ar)^3 = 1728, which implies

ar = root%283%2C1728%29 = 12; (3)

hence,

r = 12%2Fa. (4)

Now, in equation (1) replace the term ar by 12, based on (3). You will get

a + 12 + ar^2 = 38, which implies

a + ar^2 = 26. (5)

Next, substitute r = 12%2Fa into equation (5), replacing "r" there. You will get

a + a%2A%28144%2Fa%5E2%29 = 26, or

a + 144%2Fa = 26.

Multiply by "a" both sides and simplify

a^2 - 26a + 144 = 0,

%28a-13%29%5E2 - 169 + 144 = 0

%28a-13%29%5E2 = 25

a - 13 = +/- sqrt%2825%29 = +/- 5.

Thus two solutions for "a" are a = 13 + 5 = 18 or a = 13 - 5 = 8.

If a = 8, then from (4) r = 12%2F8 = 3%2F2.

If a = 18, then from (4) r = 12%2F18 = 2%2F3.

In the first case, if a = 8, then the three terms are 8, 8%2A%283%2F2%29 = 12 and 8%2A%283%2F2%29%5E2 = 18.

In this case, the sum of terms is 8 + 12 + 18 = 38, so this solution does work.

In the second case, if a = 18, then the three terms are 18, 18%2A%282%2F3%29 = 12 and 18%2A%282%2F3%29%5E2 = 8.

In this case, the sum of terms is 18 + 12 + 8 = 38, so this solution does work, too.

ANSWER. The problem has two solution:

a) first term is 18; the common difference is 2%2F3 and the progression is 18, 12, 8.

b) first term is 8; the common difference is 3%2F2 and the progression is 8, 12, 18.

4 0

3 years ago

You begin with $25 in a savings account and $50 in a checking account each week you deposit five dollars into savings and $10 in

Veseljchak [2.6K]

The first week.
The first week there is 30 dollars in the saving account and 60 dollars in the checking account.

7 0

4 years ago

Read 2 more answers

Estimate the quotient 57.8 ÷81

riadik2000 [5.3K]

57.8 ≈ 60
81 ≈ 80

57.8/ 81
≈ 60/80
≈ 3/4
≈ 0.75

The quotient 57.8/ 81 is approximately equal to 0.75~

6 0

3 years ago

Read 2 more answers

☆15 POINTS AND MARKED BRAINLIEST IF CORRECT☆<br>look at the image above to view the question!

swat32

Answer:

3125 bacteria.

Step-by-step explanation:

We can write an exponential function to represent the situation.

We know that the current population is 100,000.

The population doubles each day.

The standard exponential function is given by:

$P(t)=a(r)^t$

Since our current population is 100,000, a = 100000.

Since our rate is doubling, r = 2.

So:

$P(t)=100000(2)^t$

We want to find the population five days ago.

So, we can say that t = -5. The negative represent the number of days that has passed.

Therefore:

$\displaystyle P(-5)=100000(2)^{-5} = 100000 \Big( \frac{1}{32}\Big) = 3125 \text{ bacteria}$

However, we dealing within this context, we really can't have negative days. Although it works in this case, it can cause some confusion. So, let's write a function based on the original population.

We know that the bacterial population had been doubling for 5 days. Let A represent the initial population. So, our function is:

$P(t)=A(2)^t$