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3 years ago

Part D 1 light-minute in miles Express your answer using three significant figures. ? mi 1 light minute Request Answer Submit

Mathematics

1 answer:

Lemur [1.5K]3 years ago

5 0

Answer:

1 light-minute ≈ 1.12×10⁷ miles, three significant figures.

Step-by-step explanation:

Light-second is equal to the distance traveled per second by light in space, which is equal to 299,792,458 metres. Other units used are light-day, light-hour and light-minute.

Significant figures are the figures or digits of a number that carry meaning and contribute to the precision of the given number.

1 light-minute = 1.118×10⁷ miles, has four significant figures.

To express this number in three significant figures, the given number is rounded.

<u>1 light-minute = 1.118×10⁷ miles ≈ 1.12×10⁷ miles, has three significant figures, as the non-zero digits are significant.</u>

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The answer is C as D is too much as 3 tons equal around 6000 pounds

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3 years ago

Solve the equation. -7 = -1 + x/3

pochemuha

Answer:

x= -18

Step-by-step explanation:

We want to isolate x ( move everything to the other side of the equation)

-7 = -1 + x/3

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3 years ago

Read 2 more answers

1. D=5.9 ft.

Shtirlitz [24]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Here's the solution ~

As we know, we can calculate the circumference of a circle in terms of its diameter as :

$\qquad \sf \dashrightarrow \:c = \pi d$

where, c = circumference and d = diameter

And also, circumference of circle is terms of radius (r) is :

$\qquad \sf \dashrightarrow \:c = 2\pi r$

Now, let's move on to questions ~

<h3>First </h3>

$\qquad \sf \dashrightarrow \:3.14 \times 5.9$

$\qquad \sf \dashrightarrow \: \approx18.53 \: ft$

<h3 />

・．━━━━━━━†━━━━━━━━━．・

<h3>Second</h3><h3 /><h3 /><h3 /><h3> $\qquad \sf \dashrightarrow \:3.14 \times 3.2$ </h3>

$\qquad \sf \dashrightarrow \: \approx10.048 \: ft$

・．━━━━━━━†━━━━━━━━━．・

<h3>Third</h3>

$\qquad \sf \dashrightarrow \:3.14 \times 6.1$

$\qquad \sf \dashrightarrow \: \approx19.15 \: ft$

・．━━━━━━━†━━━━━━━━━．・

<h3>Fourth</h3>

$\qquad \sf \dashrightarrow \:2×3.14 \times 3.7$

$\qquad \sf \dashrightarrow \: \approx2×11.62 \: m$

$\qquad \sf \dashrightarrow \: \approx23.24 \: m$

・．━━━━━━━†━━━━━━━━━．・

<h3>Fifth </h3>

$\qquad \sf \dashrightarrow \:2×3.14 \times 6.2$

$\qquad \sf \dashrightarrow \: \approx2× 19.47 \: units$

$\qquad \sf \dashrightarrow \: \approx38.94 \: m$

・．━━━━━━━†━━━━━━━━━．・

<h3>Sixth</h3>

$\qquad \sf \dashrightarrow \:2×3.14 \times 5.1$

$\qquad \sf \dashrightarrow \: \approx2×16.01 \: ft$

$\qquad \sf \dashrightarrow \: \approx \: 32.02m$

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7 0

2 years ago

Plz helppp..........!!!!!!!!!!!

Setler [38]

Answer:

~ <em>50 centimeters of the poster ~</em>

Step-by-step explanation:

Let us plan out our steps, and solve for each:

<em>1. Given the information, let us create a proportionality as such:</em>

<em />

5 = 1 ⇒ x - centimeters of the poster

x 10

<em>2. Now let us cross multiply, and solve through simple algebra for x:</em>

5 * 10 = x,

x =<em> 50 centimeters of the poster </em>

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3 years ago

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mart [117]

Start at -8 move to the left 8 more times,. You get -16.

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3 years ago