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3241004551 [841]
3 years ago
8

Part D 1 light-minute in miles Express your answer using three significant figures. ? mi 1 light minute Request Answer Submit

Mathematics
1 answer:
Lemur [1.5K]3 years ago
5 0

Answer:

1 light-minute ≈ 1.12×10⁷ miles, three significant figures.

Step-by-step explanation:

Light-second is equal to the distance traveled per second by light in space, which is equal to 299,792,458 metres. Other units used are light-day, light-hour and light-minute.

Significant figures are the figures or digits of a number that carry meaning and contribute to the precision of the given number.

1 light-minute = 1.118×10⁷ miles, has four significant figures.

To express this number in three significant figures, the given number is rounded.

<u>1 light-minute = 1.118×10⁷ miles ≈ 1.12×10⁷ miles, has three significant figures, as the non-zero digits are significant.</u>

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Brilliant_brown [7]

Answer:

C=hypotenuse [h]=50 feet

A=[base]=40foot.

B=perpendicular [p]=?

Area =?

we have

By using Pythagoras law

p²+b²=h²

B²=40²=50²

B²=50²-40²

B=√900

B=30feet

we have

Area of triangle =½×A×B=½×30×40=600feet²

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3 years ago
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A hotel has $504 to buy new pillows. If the cost of each pillow is $6, how many pillows will the hotel be able to buy? A) 78 B)
Naddik [55]
Hello there! 
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In the figure, AB║CD and ∠EIA is congruent to ∠GJB Complete the following statements to prove that ∠IKL is congruent to ∠DLH.
REY [17]

Here it is given that AB || CD

< EIA = <GJB

Now

∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)

∠EIA  ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)

∠IKL + ∠IKC 180° and ∠DLH +  ∠JLD =180° (Linear Pair Theorem)

So

m∠IKL + m∠IKC = 180°       ....(1)

But ∠IKC  ≅ ∠JLD

m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)

So we have

m∠IKL + m∠JLD = 180°

∠IKL and ∠JLD are supplementary angles.

But ∠DLH and ∠JLD are supplementary angles.

∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)

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3 years ago
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aleksandrvk [35]
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The liquid volume of Eric's water bottle is 3 liters. What is the approximate liquid volume of 5 of these bottles in milliliters
stepan [7]

Answer:

Option D is correct

The approximate liquid volume of 5 of these bottles is, 15,000 milliliters.

Step-by-step explanation:

Given the statement: The liquid volume of Eric's water bottle is 3 liters.

Using conversion:

1 liters = 1000 milliliters

Convert 3 liters into milliliters;

using above conversion:

3 liters  = 3 \times 1000 = 3000 milliliters.

To find the volume of liquid in 5 of these bottles in milliliters:

Volume of liquid in 1 bottle is, 3000 milliliters.

then;

Volume of liquid in 5 bottles  = 5 \times 3000 = 15,000 milliliters.

Therefore, approximate liquid volume of 5 of these bottles is, 15,000 milliliters

6 0
3 years ago
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