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2 years ago

Match each logarithmic equation to its corresponding x-value.

Mathematics

2 answers:

mario62 [17]2 years ago

4 0

Answer:

please check photos for explanation.

Elina [12.6K]2 years ago

3 0

I think the answer is 5

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If the equation is an identity or if it has no solution, write identity or no solution.

Ksenya-84 [330]

Answer:

7n + 5 − 9n = 8 − 2n − 3 = true

-2 n + 5 = 5 - 2 n = true

Step-by-step explanation:

Left-hand side:

Simplify the following:

7 n - 9 n + 5

Grouping like terms, 7 n - 9 n + 5 = 5 + (7 n - 9 n):

5 + (7 n - 9 n)

7 n - 9 n = -2 n:

Answer: -2 n + 5

____________________________

Right-hand side:

Simplify the following:

-2 n - 3 + 8

Grouping like terms, -2 n - 3 + 8 = (8 - 3) - 2 n:

(8 - 3) - 2 n

8 - 3 = 5:

Answer: 5 - 2 n

7 0

4 years ago

‼️‼️‼️‼️‼️‼️‼️‼️‼️heLP pls ‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️

Klio2033 [76]

Answer:

#3 i think you have to put them least to greatest.

Step-by-step explanation:

i dont know the others im having a brainfart

4 0

3 years ago

A triangle has vertices (-1, 2), (3, 1), and (7, 2). What is the approximate perimeter of the triangle? Round your answer to the

larisa86 [58]

Use the distance formula to find the length of the sides, then add them up to find the perimeter.

$\sf d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

For points in the form of (x1, y1), (x2, y2).

(-1, 2), (3, 1)

$\sf d=\sqrt{(3+1)^2+(1-2)^2}$

$\sf d=\sqrt{(4)^2+(-1)^2}$

$\sf d=\sqrt{16+1}$

$\sf d=\sqrt{17}$

(3, 1), (7, 2)

$\sf d=\sqrt{(7-3)^2+(2-1)^2}$

$\sf d=\sqrt{(4)^2+(1)^2}$

$\sf d=\sqrt{16+1}$

$\sf d=\sqrt{17}$

(7, 2), (-1, 2)

$\sf d=\sqrt{(-1-7)^2+(2-2)^2}$

$\sf d=\sqrt{(-8)^2+(0)^2}$

$\sf d=\sqrt{64+0}$

$\sf d=\sqrt{64}=8$

So the perimeter will be:

$\sf 8+\sqrt{17}+\sqrt{17}\approx\boxed{\sf 16.25}$