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Serhud [2]
2 years ago
11

1. If f(x) = 2x - 3, find the following: a. f(-2) = b. f(7) = c. f(-4) =

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
5 0
A. 2(-2) - 3
-4 - 3
-7

b. 2(7) - 3
14 - 3
11

2(-4) - 3
-8 - 3
- 11
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If r and s are positive integers, is \small \frac{r}{s} an integer? (1) Every factor of s is also a factor of r. (2) Every prime
Yuri [45]

Answer:

<em>If statement(1) holds true, it is correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em>If statement(2) holds true, it is not necessarily correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em></em>

Step-by-step explanation:

Given two positive integers r and s.

To check whether \small \frac{r}{s} is an integer:

Condition (1):

Every factor of s is also a factor of r.

r \geq s

Let us consider an example:

s = 5^2 \cdot 2\\r = 5^3 \cdot 2^2

\dfrac{r}{s} = \dfrac{5^3\cdot2^2}{5^2\cdot2} = 10

which is an integer.

Actually, in this situation s is a factor of r.

Condition 2:

Every prime factor of <em>s</em> is also a prime factor of <em>r</em>.

(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)

Let

r = 2^2\cdot 5\\s =2^4\cdot 5

\dfrac{r}{s} = \dfrac{2^3\cdot5}{2^4\cdot5} = \dfrac{1}{2}

which is not an integer.

So, the answer is:

<em>If statement(1) holds true, it is correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em>If statement(2) holds true, it is not necessarily correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em></em>

8 0
3 years ago
Plz help me asap plz i will mark you as brainlist
Masteriza [31]

Answer:

$420

Step-by-step explanation:

130x12=1560

165x12=1980

1980-1560=420

4 0
2 years ago
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Answer: 56.549 or 56.5

Explanation:

C= (pie) 3.14 * d = 2 * 3.14 * r

D= 18

C = 3.14 * 18 = 18 * 3.14

C = 56.549 or 56.5

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Answer:

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Step-by-step explanation:

i just multiplied them together umm yeah...

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