Question

What is the line that passes through points 6,9 and 11,2

Answer 1

The final equation of line passing through (6,9) and (11,2)

$y=-\frac{7}{5}x+\frac{87}{5}$

Further explanation:

The general form of equation is:

$y=mx+b$

We have to find the slope first

$m=\frac{y_2-y_1}{x_2-x_1}\\Here\\(x_1,y_1)=(6,9)\\(x_2,y_2)=(11,2)\\Putting\ the\ values\\m=\frac{2-9}{11-6}\\=-\frac{7}{5}$

Putting the value of m in general form

$y=-\frac{7}{5}x+b$

For finding the value of b, putting (6,9) in equation

$9=-\frac{7}{5}(6)+b\\9=-\frac{42}{5}+b\\9+\frac{42}{5}=b\\b=\frac{45+42}{5}$

$b=\frac{87}{5}$

Putting the values of b and m

The final equation of line passing through (6,9) and (11,2)

$y=-\frac{7}{5}x+\frac{87}{5}$

Keywords: Equation of line, Slope

Learn more about equation of line at:

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