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2 years ago

HELP PLEASE!!!!!! Only 5 more minutes till i turn it in!!!

Mathematics

2 answers:

Stella [2.4K]2 years ago

7 0

Hi!

The Triangle Angle Sum Theorem states that the sum of the interior angles in all triangles will always be 180 degrees.

We can set up an equation with the given information:

40 + (2x - 30) + (x + 20) = 180

Remove parentheses:

40 + 2x - 30 + x + 20 = 180

Combine like terms:

30 + 3x = 180

Subtract 30 from both sides:

3x = 150

Divide both sides by 3:

x = 50

Now, the problem wants us to solve for angle B.

Angle B is (2x - 30) degrees. We know the value of x, so we just have to substitute:

(2x - 30)

(2(50) - 30)

100 - 30

Therefore, angle B is 70 degrees.

GarryVolchara [31]2 years ago

5 0

Answer:

<B = 70°

Step-by-step explanation:

First we need to find x, lets plugin these two equations.

2x - 30 = x + 20

Then find like terms

2x = x + 50 =

x = 50

Then we plugin 50 for x

2(50) - 30 =

100 - 30 = 70

<B = 70°

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Read 2 more answers

Location is known to affect the number, of a particular item, sold by an auto parts facility. Two different locations, A and B,

Mama L [17]

We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

$\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$

In order to use t*, we need to check conditions for using a t-distribution first.

Random for both samples -- NOT STATED in the problem ∴ proceed with caution!
Independence for both samples: 130 < all items sold at Location A; 180 < all items sold at Location B -- we can reasonably assume this is true
Normality: CLT is not met; n < 30 for both locations A and B ∴ proceed with caution!

Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.

Solve for t*:

We need the tail area first.

$\displaystyle \frac{1-.9}{2}= .05$

Next we need the degree of freedom.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

df for A: 13 - 1 = 12
df for B: 18 - 1 = 17
df for A - B: |12 - 17| = 5

Use a calculator or a t-table to find the corresponding t-score for df = 5 and tail area = .05.

t* = -2.015

Now we can use the formula at the very top to construct a confidence interval for two sample means.

$\overline {x}_A=39$
$s_A=8$
$n_A=13$
$\overline {x}_B = 55$
$s_B=2$
$n_B=18$
$t^{*}=-2.015$

Substitute the variables into the formula: $\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$ .