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2 years ago

Please I need help with this

Mathematics

1 answer:

Vera_Pavlovna [14]2 years ago

6 0

Step-by-step explanation:

The x are the values that you have been given

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I need help please.

exis [7]

Pretty sure the answer is 20
Hope this helps :)

3 0

3 years ago

Read 2 more answers

Let Y1 and Y2 be independent exponentially distributed random variables, each with mean 7. Find P(Y1 > Y2 | Y1 < 2Y2). (En

ArbitrLikvidat [17]

Y₁ and Y₂ are independent, so their joint density is

$f_{Y_1,Y_2}(y_1,y_2)=f_{Y_1}(y_1)f_{Y_2}(y_2)=\begin{cases}\frac1{49}e^{-\frac{y_1+y_2}7}&\text{for }y_1\ge0,y_2\ge0\\0&\text{otherwise}\end{cases}$

By definition of conditional probability,

P(Y₁ > Y₂ | Y₁ < 2 Y₂) = P((Y₁ > Y₂) and (Y₁ < 2 Y₂)) / P(Y₁ < 2 Y₂)

Use the joint density to compute the component probabilities:

• numerator:

$P((Y_1>Y_2)\text{ and }(Y_1$

$=\displaystyle\frac1{49}\int_0^\infty\int_{\frac{y_1}2}^{y_1}e^{-\frac{y_1+y_2}7}\,\mathrm dy_2\,\mathrm dy_1$

$=\displaystyle-\frac17\int_0^\infty\int_{-\frac{3y_1}{14}}^{-\frac{2y_1}7}e^u\,\mathrm du\,\mathrm dy_1$

$=\displaystyle-\frac17\int_0^\infty\left(e^{-\frac{2y_1}7} - e^{-\frac{3y_1}{14}}\right)\,\mathrm dy_1$

$=\displaystyle-\frac17\left(-\frac72e^{-\frac{2y_1}7} + \frac{14}3 e^{-\frac{3y_1}{14}}\right)\bigg|_0^\infty$

$=\displaystyle-\frac17\left(\frac72 - \frac{14}3\right)=\frac16$

• denominator:

$P(Y_1$

(I leave the details of the second integral to you)

Then you should end up with

P(Y₁ > Y₂ | Y₁ < 2 Y₂) = (1/6) / (2/3) = 1/4

5 0

2 years ago

PLSSSS HELLLPPP WILL GIVE BRAINLIESTTT!!!!!!!!!

Lerok [7]

Answer: -3/2

Step-by-step explanation:

There are two methods to find the slope

METHOD 1. Rise/Run

Rise: the y-axis value

Run: the x-axis value

In the graph, rise/run=3/2

The line is going down, so it should be negative

-3/2

Hope this helps!! :)

Please let me know if you have any question or need further explanation

5 0

3 years ago

How do you do these 4 questions and the reasons?

Afina-wow [57]

Step-by-step explanation:

"There are several flights that have very long delays."

True. On the boxplot, we can see several outliers greater than the maximum.

"More than 25% of flights are either exactly on time or arrive early."

False. According to the 5 number summary, 25% of the flights are between -55 and 13. So less than 25% of the flights are on time or early.

"About 50% of flights are delayed between 13 and 35 minutes."

False. According to the 5 number summary, 25% of the flight times are less than 13 minutes, and 50% of the flights are less than 35 minutes. So 25% of the flights are delayed between 13 and 35 minutes, not 50%.

"About 25% of flights are delayed by more than 78 minutes."

True. According to the 5 number summary, 75% of the flights are delayed less than 78 minutes. Which means 25% of the flights are delayed more than 78 minutes.

4 0

3 years ago

Please help me on this

AlekseyPX

9514 1404 393

Answer:

10 ft

Step-by-step explanation:

The midsegment length is the average of the other two lengths.

(QR +PS)/2 = TU

QR +PS = 2×TU . . . . . . . . . . . . . . . multiply by 2

QR = 2×TU -PS = 2(14 ft) -18 ft . . . subtract PS; substitute given values

QR = 10 ft

8 0

3 years ago