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const2013 [10]
2 years ago
10

ACTIVITY 1: LET'S PRACTICE!

Mathematics
1 answer:
V125BC [204]2 years ago
8 0

Answer:

1. YES

1. YES2. YES

1. YES2. YES3.YES

4.NO

Hope it helps

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How much greater is the area of a square with a side length of 9 inches than the area of a circle with a radius of 3 inches?
fredd [130]
The area of the square is 81 sq in, and the area of the circule is (3.14)(3 in)^2, or approx 3.14(9) sq in, or approx  28.27 sq in.

Subtract:  81 sq in - 28.27 sq in = approx. 52.73 sq in.

The difference is 52.73 sq in; the square is larger, the circle smaller.
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3 years ago
Please help URGENT! WILL GIVE BRAINLEST AND 30 POINTS
ivanzaharov [21]

Answer:

The answer you are looking for is the letter B on your assignment hun. Merry almost Christmas☃️

5 0
2 years ago
Read 2 more answers
If the customer rolls the dice and rents a second movie every Thursday for 20 consecutive weeks, what is the total amount that t
VMariaS [17]

Answer:

The expected amount for a duration of 20 weeks is $9.4

<em></em>

Step-by-step explanation:

Read attachment to understand the complete question

From the question, we have the following given parameters:

x = Amount paid for a second movie

E(x) = 0.47 --- Expected value of x

SD(x) = 0.15 --- Standard deviation of x

Required

Determine the total amount paid for a second movie for 20 weeks

The required implies that we calculate the expected value for a duration of 20 weeks.

i.e.

n = 20

If

E(x) = 0.47

Then:

E(nx) = n * E(x)

Substitute 20 for n

E(20x) = 20 * E(x)

Substitute 0.47 for E(x)

E(20x) = 20 * 0.47

E(20x) = 9.4

<em>Hence, the expected amount for a duration of 20 weeks is $9.4</em>

6 0
3 years ago
Temperature transducers of a certain type are shipped in batches of 50. A sample of 60 batches was selected, and the number of t
Contact [7]

Answer:

The number of six non conforming transducers at most =54/60=0.9

The number of fewer than six non conforming transducers =51/60=0.85

The number of at least six non conforming transducers at most =30/60=0.5

d) The center of the histogram is around 2 or 3 and it shows that there is some positive skewness in the data

Step-by-step explanation:

Relative Frequency Frequency       x

6/60=0.1                            6                   0

0.2                                    12                    1

0.2                                   12                     2

0.25                            15                      3

0.1                                    6                       4

0.05                               3                 5

0.05                               3                 6

0.0167                              1                          7

<u>0.033                               2                  8</u>

<u>∑                                    60                   </u>

The number of six non conforming transducers at most

= 6+12+12+15+6+3= 54

The number of six non conforming transducers at most =54/60=0.9

The number of fewer than five non conforming transducers

= 6+12+12+15+6 = 51

The number of fewer than six non conforming transducers =51/60=0.85

 

The number of at least six non conforming transducers

2+1+3+3+6+15= 30

The number of at least six non conforming transducers at most =30/60=0.5

We plot the histogram by placing the percentages (or relative frequency *100) on the y –axis and the X on the x-axis.

The center of the histogram is given by the mean of the distribution which in this case is = ∑fx/∑f= 161/60= 2.683

So option d is the best answer

d) The center of the histogram is around 2 or 3 and it shows that there is some positive skewness in the data

Because at the center (between 2 and 3) the curve is increasing

6 0
2 years ago
What is an expression equivalent to 11(5)+11(11)
inessss [21]

Answer:

176

Step-by-step explanation:

just simplify the given mathematical statement

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2 years ago
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