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2 years ago

ACTIVITY 1: LET'S PRACTICE!

Mathematics

1 answer:

V125BC [204]2 years ago

8 0

Answer:

1. YES

1. YES2. YES

1. YES2. YES3.YES

4.NO

Hope it helps

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What is the probability of the occurrence of a number that is odd or less than 5

yaroslaw [1]

Answer:

Hence the probability of getting a number less than 5 is 2/3.

Step-by-step explanation:

6 0

1 year ago

Read 2 more answers

Describe how the graphs of y=1/2x +7 is the same and different from the graph of y= 12x + 7

TiliK225 [7]

Answer:

the slope of the line for y=12x+7 is steeper compared to the other equation

they both have the same y-intercept of y=7

Step-by-step explanation:

i just plugged it into desmos and looked at the graph

hope this helps <3

3 0

3 years ago

Substitute y = 2x + 1 y = 3x - 1

Svet_ta [14]

2x+ 1 = 3x - 1 ;
1 + 1 = 3x - 2x ;
2 = x ;
x = 2 ;
Then, y = 2x2 + 1 = 5 ;

4 0

3 years ago

HIJK is a rectangle. Find the value of x and find the length of each diagonals. If hj=19+2x and ik=3x+22

viva [34]

Hj and ik are opposite sides of the rectangle so they areequal in length.

19 + 2x = 3x + 22
19-22 = 3x-2x
x = -3

We can't find the length of the diagonals as we have no information about the width.

8 0

3 years ago

Select all possible values for x in the equation x^3=375?

Helga [31]

<h2>Hello!</h2>

The answers are:

The possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

To solve the problem, we need to remember the following properties of the exponents and roots:

$a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}$

Then, we are given the expression:

$x^{3}=375$

So, finding "x", we have:

$x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}$

Hence, the possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

Have a nice day!

7 0

3 years ago