Answer:
using pythagoras theorem
H^2=P^2+B^2
here h=MN ,opposite(P) be 15 and adjacent(B) be 16
(MN)2=15^2+16^2
(MN)^2=225+256
MN=
MN=21.93
after rounding off MN=21.9
Step-by-step explanation:
She saved up a total of $82.60, and had to spend a total of $60.90, so she would have $21.70 left and need to save up another $180.40, hope this helps
You move the decimal 3.4, 2 places to the right and get 340 then you move the decimal 4.37, 2 placeto the right and you multiply 340 and 437 and you get 14858 and you move 3 decimal place to the left because you moved 3 decimal place so you have to move it back and you get 14.858
Answer:
The correct answer is option D. 5.7 units
Step-by-step explanation:
It is given a square, Its diagonals meet to form four right angles
<u>To find the value of x</u>
From the figure we can see that the triangle with sides x, x, 8 have angles 45°,45° and 90°
If the angles are 45°,45° and 90° then sides are in the ratio 1 : 1 : √2
Here x : x : 8 = 1 : 1 : √2
Therefore x = 8√2 = 8/1.414 = 5.6577 ≈ 5.7 units
Therefore the correct answer is option D 5.7 units
The angle ∠EJS is bisected by the diagonal JS to form an angle of 62°
Response:
<h3>What properties of a rhombus can be used to find ∠EJS = 62?</h3>
Properties of a rhombus:
The lengths of the sides of a rhombus are equal
The measure of the opposite angles of a rhombus are equal
The diagonals bisect the interior angles of a rhombus
Given that JOSE is a rhombus, and ∠ESO = 124°, we have;
∠EJO = ∠ESO = 124° opposite angles of a rhombus
∠EJS = ∠OJS definition of bisected angle ∠EJO
∠EJS + ∠OJS = ∠EJO by angle addition
- ∠EJS + ∠OJS = 2×∠EJS = ∠EJO = 124°

Learn more about a rhombus here:
brainly.com/question/10689502