Answer:
Approximately normal for large sample sizes
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean 
and standard deviation 
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation 
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question:
The distribution is unknown, so the sampling distribution will only be approximately normal when n is at least 30.
So the correct answer should be:
Approximately normal for large sample sizes
41.25 because you divide the cost into the profit and that equals 41.25
Answer:
Matt made the error
Step-by-step explanation:
Matt used the diameter of the sphere instead of the radius.
Answer:
4x² - 10x + 1
Step-by-step explanation:
(3x-1) + (x+2) + (3x² - 11x) + (x² - 3x)
3x - 1 + x + 2 + 3x² - 11x + x² - 3x
1 - 10x + 4x²
= 4x² - 10x + 1
ANSWER:
86 YELLOW
y=yellow
b=blue
y=5b-9
y+b=105
5b-9+b=105
6b=114
b=19
