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Y_Kistochka [10]
2 years ago
14

A total of 590 tickets were sold for the school play. They were either adult tickets or student tickets. There were 60 fewer stu

dent tickets sold than adult tickets. How many adult tickets were sold?
Mathematics
2 answers:
julia-pushkina [17]2 years ago
7 0

Answer:

  325 adult tickets

Step-by-step explanation:

This "sum and difference" problem can be solved by assigning a single variable to the quantity you want to know. Let 'a' represent the number of adult tickets sold. Then (a-60) is the number of student tickets sold, and the total number sold is ...

  a +(a -60) = 590

  2a = 590 +60

  a = 650/2 = 325

There were 325 adult tickets sold.

__

<em>Check</em>

325-60 = 265 student tickets were sold, for a total of 325+265 = 590.

_____

<em>Additional comment</em>

You may have noticed that the larger number of tickets (number of adult tickets) was found to be the average of the two numbers given in the problem statement. That will generally be the case for a "sum and difference" problem.

Masteriza [31]2 years ago
6 0

Answer:x+x-61=489

2x=489+61

x=550/2

x=275 adults

Step-by-step explanation:

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2 years ago
A flash disk has the capacity of storing 1 megabyte of data. How many kilobytes of data can be stored in the same flash disk​
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For this sort of problem, you need to be familiar with prefixes.

So:

megabyte = 1 *10^6 bytes

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and a regular byte would just be 1

Now, you will need to do a conversion:

1megabyte*\frac{1*10^6bytes}{1megabyte}*\frac{1*10^{-3}kilobyte}{1byte}

I'm going to explain this just in case, but we convert megabytes to regular bytes in the first half by using the information I gave you above. (In one megabyte, there are 1*10^6 bytes!)

In the second fraction thought, remember one kilobyte is 1*10^3 bytes. However, you usually only see one of each thing on the bottom of fractions, so you need to add a negative sign to the 3. (technically you could just do \frac{1kilobyte}{1*10^3bytes}, but I think it is more correct to do write it out how I did).

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6 0
2 years ago
Thomas needed a load. he borrowed 24,000$ from the bank at a rate of 8.25% of simple interest for 36 months. what was the total
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