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Y_Kistochka [10]
2 years ago
14

A total of 590 tickets were sold for the school play. They were either adult tickets or student tickets. There were 60 fewer stu

dent tickets sold than adult tickets. How many adult tickets were sold?
Mathematics
2 answers:
julia-pushkina [17]2 years ago
7 0

Answer:

  325 adult tickets

Step-by-step explanation:

This "sum and difference" problem can be solved by assigning a single variable to the quantity you want to know. Let 'a' represent the number of adult tickets sold. Then (a-60) is the number of student tickets sold, and the total number sold is ...

  a +(a -60) = 590

  2a = 590 +60

  a = 650/2 = 325

There were 325 adult tickets sold.

__

<em>Check</em>

325-60 = 265 student tickets were sold, for a total of 325+265 = 590.

_____

<em>Additional comment</em>

You may have noticed that the larger number of tickets (number of adult tickets) was found to be the average of the two numbers given in the problem statement. That will generally be the case for a "sum and difference" problem.

Masteriza [31]2 years ago
6 0

Answer:x+x-61=489

2x=489+61

x=550/2

x=275 adults

Step-by-step explanation:

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Step-by-step explanation:

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7 0
3 years ago
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Hence, Option A is not the correct answer.

Option B: \sqrt[9]{xy^2}

The expression can be written as ({xy^2})^{\frac{1}{9}

Applying exponent rule, we get,

x^{\frac{1}{9}} y^{\frac{2}{9}}

Thus, the expression \sqrt[9]{xy^2} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option B is not the correct answer.

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The expression can be written as x(y^9)^{\frac{1}{2} }

Applying exponent rule, we get,

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Thus, the expression x\sqrt{y^9} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option C is not the correct answer.

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Applying exponent rule, we get,

xy^{\frac{2}{9}}

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