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malfutka [58]
3 years ago
5

The area of a rectangular city park is 25/54 square miles. The length of the park is 5/9 miles what is the width in the miles of

the park
Mathematics
1 answer:
kotykmax [81]3 years ago
7 0
Note that A=lw, where A is the area, l is the length, and w is the width.  Substituting our values in, we have:

\frac{5w}{9} = \frac{25}{54}

Multiplying by \frac{9}{5} gives:

w=\frac{5}{6}

So the width is \frac{5}{6} miles.
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Step-by-step explanation:

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german

Answer:

In order to have ran 33 miles, Bobby would have to attend <em>32 track practices.</em>

Step-by-step explanation:

Solving this problem entails of uncovering the amount of track practices Bobby must attend in order to have ran 33 miles. Start by reading the problem carefully to break down the information provided.

You can see that Bobby has already ran one mile on his own. This is important to remember for later. The problem also states that he expects to run one mile at every track practice.

Setting up an equation will help us solve. Here is how we could set up the equation:

(<em>amount of miles already ran</em> = 1) + (<em>number of track practices</em> = x) = (<em>total miles to run</em> = 33)

1 + x = 33

The equation is now in place. You can solve this, or isolate <em>'x',</em> by using the subtraction property of equality. This means we will subtract one from both sides of the equation, thus isolating the variable.

1 + x = 33

1 - 1 + x = 33 - 1

x = 32

The variable is the only term left on the left side of the equation. This means Bobby must attend track practice <em>32 times</em> in order to have ran 33 miles.

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Answer:

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Step-by-step explanation:

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In the diagram below <br> Please help I’ll give brainliest
Luda [366]

Answer:

m<GFA = 110

Step-by-step explanation:

1. ABCD - parallelogram                          Definition of a parallelogram

                                                                   (AB ll CD) (AD ll BC)

2. m<B + m<C = 180                                    Consectuive angles in a

   110 + m<C = 180                                       parallelogram are supplementary

    m<C = 70                                    

3. m<GCB = 1/2 m<C                                  Definition of angles bisector

   m<GCB = 70

4. m<B = m<D = 110                                    Opposite angles in a

                                                                    parrallelogram are congruent

5. m<CDG = 1/2 m<D                                 Defintion of an angle bisector

  m<CDG = 55

6. m<GCB+m<CDG+m<CGD=180              Sum of anlges in a triangle (ΔCDG)

  70 + 55 + m<CGD = 180

   125 + m<CGD = 180

   m<CGD = 55

7. m<CGD + m<DGF = 180                            Linear pair, supplmentary angles

  55 + m<DGF = 180

  m<DGF = 125

8. m<C = m<A = 70                                     Opposite angles in a paralellogram

                                                                     are congruent

9. m<ADG = 1/2m<D                                       Definiton of an angle bisector

  m<ADG = 55

10.m<ADG+m<DFG+m<GFA+m<A=360        Sum of angles in quadrilateral

   55 + 125 + m<GFA + 70 = 360                    DGFA

    m<GFA + 250 = 360

   m<GFA = 110

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3 years ago
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