Answer:
Step-by-step explanation:
I see you're in college math, so we'll solve this with calculus, since it's the easiest way anyway.
The position equation is
That equation will give us the height of the rock at ANY TIME during its travels. I could find the height at 2 seconds by plugging in a 2 for t; I could find the height at 12 seconds by plugging in a 12 for t, etc.
The first derivative of position is velocity:
v(t) = -3.72t + 15 and you stated that the rock will be at its max height when the velocity is 0, so we plug in a 0 for v(t):
0 = -3.72t + 15 and solve for t:\
-15 = -3.72t so
t = 4.03 seconds. This is how long it takes to get to its max height. Knowing that, we can plug 4.03 seconds into the position equation to find the height at 4.03 seconds:
s(4.03) = -1.86(4.03)² + 15(4.03) so
s(4.03) = 30.2 meters.
Calculus is amazing. Much easier than most methods to solve problems like this.
Answer:
<u>The percent decrease of the microwave from the original price to the sale price is 24%</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
Original price of a microwave = $ 75
Mark-up price of the microwave = $ 90
Sale price of the microwave = $ 57
2. What is the percent decrease from the original price to the sale price?
For answering this question we will use the Direct Rule of Three this way:
Price Percentage
75 100%
57 x
75x = 57 * 100
75x = 5,700
x = 5,700/75
x = 76
76 = 100 - 24
<u>The percent decrease of the microwave from the original price to the sale price is 24%</u>
Answer:
-9≤y≤0
Step-by-step explanation:
-4≤x≤4 DOMAIN
-9≤y≤0 RANGE
I'm pretty sure this is correct but I haven't done it in a while
Answer:
Step-by-step explanation:
We have been given two expressions 
and
Now we need to find out least common multiple of these two expressions.
First we need to find out what is common factor of both expressions. and
Least common multiple means find the expression which can be divided by both expressions.
15 and 6 both goes into 30
so 30 is part of LCM (least common multiple )
Now pickup the highest exponent of each variable.
So we get 
Hence required least common multiple is
