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MrMuchimi
3 years ago
6

The number of mosquitoes M(x), in millions, in a certain area depends on the June rainfall x, in inches: M(x) = 13 x - x2. What

rainfall produces the maximum number of mosquitoes
Mathematics
1 answer:
My name is Ann [436]3 years ago
4 0

Answer:

The number of mosquitoes is maximum for 6.5 inches rainfall.

Step-by-step explanation:

The given function is

M(x)=13x-x^2                   .... (1)

where, M(x) is number of mosquitoes in millions and x the June rainfall in inches.

We need to find the rainfall that produces the maximum number of mosquitoes.

Differential the above function with respect to x.

M'(x)=13-2x               .... (2)

Equate first derivative equal to 0.

13-2x=0

2x=13

x=\frac{13}{2}=6.5

Differential function (2) with respect to x.

M''(x)=-2

Double derivative is negative. So, the value of function is maximum at x=6.5.

Therefore, the number of mosquitoes is maximum for 6.5 inches rainfall.

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If a and b are both integers and b does not equal 0, then -(a/b) = (-a)/b = a/(-b) Choose two values for a and b. see if those v
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a=4 , b=3  These values make the equation true .

<u>Step-by-step explanation:</u>

Here we have , If a and b are both integers and b does not equal 0, then -(a/b) = (-a)/b = a/(-b) Choose two values for a and b. We need to find if those values make the equation true . Let's find out:

We have the following equation:

-(a/b) = (-a)/b = a/(-b) , Let a=4 , b=3 , So

⇒ -(a/b) = (-a)/b = a/(-b)

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