Question

Please help me as soon as posable!! In hurry!!(24 points)

Answer 1

The sequence is geometric, so

$a_n = r a_{n-1}$

for some constant r. From this rule, it follows that

$a_3 = r a_2 \implies 20 = 2r \implies r = 10$

and we can determine the first term to be

$a_2 = r a_1 \implies 2 = 10 a_1 \implies a_1 = \dfrac15$

Now, by substitution we have

$a_n = r a_{n-1} = r^2 a_{n-2} = r^3 a_{n-3} = \cdots$

and so on down to (D)

$a_n = r^{n-1} a_1 = 10^{n-1} \cdot \dfrac15$

(notice how the exponent on r and the subscript on a add up to n)