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Sholpan [36]
3 years ago
8

Please find the ordered pair for each point.

Mathematics
1 answer:
Lyrx [107]3 years ago
4 0
<span>Plot and locate points on a coordinate plane.</span>
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Pls help I hate math rectangular prism
nekit [7.7K]

Answer:

352.5cm^{2}

Step-by-step explanation:

A=3Rectangles+2Triangles\\=3*7.5*13.5+2*.5*6.5*7.5=352.5cm^{2}

8 0
3 years ago
What is five thousand two hundred twenty-five and seventy-two thousandths expressed in standard form?
miv72 [106K]
5,225.072 is the standard form. 
6 0
3 years ago
Read 2 more answers
A theater group made appearances in two cities. The hotel charges before tax in the second city were $1500 lower than in the fir
KonstantinChe [14]

Answer:

The hotel bill in the first city before tax would be $ 650

Step-by-step explanation:

Let x be the hotel charges ( in dollars ) before tax in the first city,

∵  Hotel charges before tax in the second city were $1500 lower than in the first.

So, the hotel charges in second city = ( x - 1500 ) dollars,

Now, percentage of tax in,

First city = 8%

Second city = 10%,

So, the total tax in both city = 8% of x + 10% of (x-1500)

=\frac{8x}{100}+\frac{10(x-1500)}{100}

=0.8x + 0.10(x-1500)

According to the question,

0.8x + 0.10(x-1500)=435

0.8x + 0.10x - 150 = 435

0.9x = 435 + 150

0.9x = 585

\implies x = \frac{585}{0.9}=650

Hence, the hotel bill in the first city before tax would be $ 650.

7 0
3 years ago
Read 2 more answers
What is the length of YZ?
Bogdan [553]

Answer: C

Hello,

Step-by-step explanation:

WZ=7-3=4

YW²=XW*WZ=3*4=12 ==> WY=2√3

In the right triangle YWZ, using the Pythagorean's theorem:

YZ²=WY²+WZ²=12+4²=28

YZ=2√7≅5.29150....

Answer C

3 0
3 years ago
Can someone help me with this problem ​
Alex_Xolod [135]

Answer:

<h2>A = 20</h2><h2>P = 6√10</h2>

Step-by-step explanation:

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A(-3, 0) , B(3, 2)

AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}

A(-3, 0), D(-2, -3)

AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

AB = CD and AD = BC

The area of a rectangle:

A=(AB)(AD)

Substitute:

A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20

The perimeter of a rectangle:

P=2(AB+AD)

Substitute:

P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}

4 0
3 years ago
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