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klasskru [66]
2 years ago
15

If x = 4cosa and y = 5tana, find (x^2/16) - (y^2/25)​

Mathematics
1 answer:
Cloud [144]2 years ago
3 0

x = 4 \cos(a)

\frac{x}{4}  =  \cos(a)  \\

( { \frac{x}{4} })^{2}  =  ({ \cos(a) })^{2}  \\

\frac{ {x}^{2} }{16}  =  {cos}^{2} (a) \\

_____________________________________________

y = 5 \tan(a)

\frac{y}{5}  =  \tan(a)  \\

( { \frac{y}{5} })^{2}  = ( { \tan(a) })^{2}  \\

\frac{ {y}^{2} }{25}  =  {tan}^{2} (a) \\

_____________________________________________

Thus ;

\frac{ {x}^{2} }{16}  -  \frac{ {y}^{2} }{25}  =  \\

{cos}^{2} (a) -  {tan}^{2} (a)

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This question was once asked before so I will put it here.

The correct answer for the question that is being presented above is this one: "x = 2; a = 5; b = 3" A 5 inch tall bamboo shoot doubles in height every 3 days. If the equation y=ab^x, where x is the number of doubling periods, represents the height of the bamboo shoot.

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A particle moves with velocity function v(t) = 2t^2 - 3t - 3, with v measured in feet per second and t measured in seconds. Find
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3 years ago
What is true about the solution of x^2/2x-6=9/6x-18?
pogonyaev

Answer:

  • x = ±√3, and they are actual solutions
  • x = 3, but it is an extraneous solution

Step-by-step explanation:

The method often recommended for solving an equation of this sort is to multiply by the product of the denominators, then solve the resulting polynomial equation. When you do that, you get ...

... x^2(6x -18) = (2x -6)(9)

... 6x^2(x -3) -18(x -3) = 0

...6(x -3)(x^2 -3) = 0

... x = 3, x = ±√3

_____

Alternatively, you can subtract the right side of the equation and collect terms to get ...

... x^2/(2(x -3)) - 9/(6(x -3)) = 0

... (1/2)(x^2 -3)/(x -3) = 0

Here, the solution will be values of x that make the numerator zero:

... x = ±√3

_____

So, the actual solutions are x = ±3, and x = 3 is an extraneous solution. The value x=3 is actually excluded from the domain of the original equation, because the equation is undefined at that point.

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<em>Comment on the graph</em>

For the graph, we have rewritten the equation so it is of the form f(x)=0. The graphing program is able to highlight zero crossings, so this is a convenient form. When the equation is multiplied as described above, the resulting cubic has an extra zero-crossing at x=3 (blue curve). This is the extraneous solution.

7 0
3 years ago
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Given h ( x ) = − 3 x + 2 , solve for x when h ( x ) = − 4.
Helga [31]

Answer:

2 is the answers for the question

Step-by-step explanation:

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8 0
2 years ago
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I’m really stuck on this. Would someone please help?
zavuch27 [327]

Since MN forms a 180 degree angle, if you subtract 148.7 from 180, you get 31.3 degrees. This means angles L and N are both 31.3 degrees. Since the parallelogram is 360 degrees total, you subtract 62.6 to account for angles L and N. The remaining degrees unaccounted for are 297.4 degrees which you then divide by two to get the value of angles O and M, which would give you 148.7 degrees for each O and M. This means that angle x is 148.7 degrees

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