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kap26 [50]
4 years ago
12

What number divided by 6 leaves a remainder of 5, divided by 5?

Mathematics
1 answer:
Orlov [11]4 years ago
4 0
Hello,

First simplify the question. 5/5=1.

Simplified question: <span>What number divided by 6 leaves a remainder of 1.

Now, multiply 6 by 1; the result, 6.

Thus, 6 is the number </span><span>divided by 6 leaves a remainder of 5, divided by 5.
*Your answer is six.*



Faith xoxo</span>
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Classify each number according to its value.
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Answer:See below and attached

Step-by-step explanation:

Given numbers

4.2×10^-6, 2.1×10^-3, 3.1×10^-2, 3.2×10^-5, 3.5×10^-4, 5.8×10^-3, 5.2×10^-4

Greater than 3.1×10^-3

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Less than 4.3 × 10^-5

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Step-by-step explanation

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3 years ago
Find each absolute value<br><br>| 4+2i |<br><br>| 5-i |<br><br>| -3i |
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How to get answer for number 1: | 4+2i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=4,\:b=2\\=\sqrt{4^2+2^2}\\Refine\\=\sqrt{20}\\\sqrt{20}=2\sqrt{5}\\=2\sqrt{5}

How to get answer for number 2: | 5-i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=5,\:b=-1\\=\sqrt{5^2+\left(-1\right)^2}\\=\sqrt{26}

Number 3 how to get answer: | -3i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=0,\:b=-3\\=\sqrt{0^2+\left(-3\right)^2}\\Refine\\=\sqrt{9}\\\sqrt{9}\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=\sqrt{3^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\\sqrt{3^2}=3\\= 3

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