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2 years ago

7

Mark plants 9 red rose bushes and 4 yellow rose bushes.What is the ratio of yellow rose bushes planted to the total number of ro

es bushes planted?

2 answers:

Shtirlitz [24]2 years ago

7 0

Answer:

4:13

Step-by-step explanation:

First as stated in the problem, mark is looking to find the ratio of Yellow rose bushes planted the <u>Total</u> amount of rose bushes planted; so therefor we must find the total amount of rose bushes planted first.

9+4 = 13.

13 will be our second number, since it is <u>Yellow : total. </u>

Then, we understand that mark plants 4 yellow rose bushes, so 4 is our first number.

Now; we can put our numbers together.

4 to 13 ; $\frac{4}{13}$ , or 4:13.

<u>I really hope this helps! Have an amazing day!</u>

brilliants [131]2 years ago

3 0

Answer: There are a total of thirteen (13) rose bushes planted but specifically there are six (6) white, five (5) red, and two (2) yellow rose bushes.

Step-by-step explanation: I done it in my head to figure it out so, i hope this helps you have a good day love.

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3 years ago

Read 2 more answers

Find the missing number of each unit rate. 155 = ?1 246 = ?1<br><br>worth 15 points!!!

alexgriva [62]

This is an incomplete question, the correct question is given below.

Find the missing number of each unit rate $\frac{15}{5}=\frac{?}{1}$ and $\frac{24}{6}=\frac{?}{1}$

Answer : The missing number of each unit rate of $\frac{15}{5}=\frac{?}{1}$ and $\frac{24}{6}=\frac{?}{1}$ are, 3 and 4 respectively.

Step-by-step explanation :

As we know that a unit rate is a rate in which 1 is present in denominator.

Or we can say that,

A unit rate is also called a single unit rate that means it will compare 1 unit of some quantity to a different units of a different quantity.

As we are given that that unit rates:

$\frac{15}{5}=\frac{?}{1}$ and $\frac{24}{6}=\frac{?}{1}$

Now we have to determine the missing number of each unit rates.

So, we can write the given expression as:

$\frac{15}{5}=\frac{?}{1}$

When are dividing 15 by 5, we get:

$\frac{15}{5}=\frac{3}{1}$

Thus, the missing number is, 3

And

$\frac{24}{6}=\frac{?}{1}$

When are dividing 24 by 6, we get:

$\frac{24}{6}=\frac{4}{1}$

Thus, the missing number is, 4

7 0

2 years ago

At time t=0 water begins to drip out of a pipe into an empty bucket. After 56 minutes 8 inches of water are in the bucket. What

oksano4ka [1.4K]

Answer:

The linear function of the bucket is $y = \frac{1}{7}\cdot x$ , where $y$ represents the amount of water, measured in inches, and $x$ is the time, measured in minutes.

Step-by-step explanation:

According to the Euclidean and Analytical Geometries, we can construct a line by knowing two distinct points on a plane. Besides, we know two different conditions for the bucket:

Initial condition of the bucket

$A(x,y) = (0\,min, 0\,in)$

Final condition of the bucket

$B(x,y) = (56\,min, 8 in)$

The equation of the line is defined by the following model:

$y = m\cdot x + b$ (1)

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$b$ - y-Intercept, dimensionless.

$m$ - Slope, dimensionless.

Based on the known conditions of the bucket, we obtain the following system of linear equations:

$b = 0$ (2)

$56\cdot m +b = 8$ (3)

The solution of the system of equations is:

$m = \frac{1}{7}$ and $b = 0$

Then, the linear function of the bucket is $y = \frac{1}{7}\cdot x$ , where $y$ represents the amount of water, measured in inches, and $x$ is the time, measured in minutes.

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2 years ago

A random sample of 625 10-ounce cans of fruit nectar is drawn from among all cans produced in a run. Prior experience has shown

diamong [38]

Answer:

10.57% probability that the mean contents of the 625 sample cans is less than 9.995 ounces.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 10, \sigma = 0.1, n = 625, s = \frac{0.1}{\sqrt{625}} = 0.004$

What is the probability that the mean contents of the 625 sample cans is less than 9.995 ounces?

This is the pvalue of Z when X = 9.995. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{9.995 - 10}{0.004}$

$Z = -1.25$

$Z = -1.25$ has a pvalue of 0.1057

So there is a 10.57% probability that the mean contents of the 625 sample cans is less than 9.995 ounces.

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2 years ago

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this makes no sense, so imma guess for u.

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