All categories

3 years ago

Help whit number 6 please! Really fast !!

Mathematics

1 answer:

ololo11 [35]3 years ago

7 0

Answer:

0 and 4

Step-by-step explanation:

You might be interested in

What's the answer to this

White raven [17]

Step-by-step explanation:

the angle CDB is the supplementary angle to 9x+10 (angle ADC).

that means they stand together for 180°. as all angles around a single point on one side of a line are together always 180°.

and then, the sum of all angles in a triangle is always 180°.

so,

CDB + (4x + 10) + 50 = 180

CDB = 180 - (9x + 10) = 180 - 9x - 19 = 170 - 9x

therefore,

(170 - 9x) + (4x + 10) + 50 = 180

170 - 9x + 4x + 10 + 50 = 180

-5x = -50

5x = 50

x = 10

angle CDB = 170 - 9x = 170 - 90 = 80°

4 0

2 years ago

Geometry Proof - Thanks in advance for the help!

RideAnS [48]

Answer:

Using reflexive property (for side), and the transversals of the parallel lines, we can prove the two triangles are congruent.

Step-by-step explanation:

Since AB and DC are parallel and AC is intersecting in the middle, you can make out two pairs of alternate interior angles. These angle pairs are congruent because of the alternate interior angles theorem. The two pairs of congruent angles are: ∠DAC ≅ ∠BCA, and ∠BAC ≅ ∠DCA.
With the reflexive property, we know side AC ≅ AC.
Using Angle-Side-Angle theorem, we can prove ΔABC ≅ ΔCDA.

8 0

3 years ago

Find the gcf 15, 18, 30 a. 450 b. 540 c. 6 d. 3

poizon [28]

Factors of 15 - 1, 3, 5, 15
Factors of 18 - 1, 2, 3, 6, 9, 18
Factors of 30 - 1, 2, 3, 5, 6, 10, 15, 30

Your answer is D

Hope I helped you :-)

6 0

3 years ago

What is ( 12 ) divided by 3??

GarryVolchara [31]

12 divides by 3 is equal to 4

4 0

3 years ago

For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

3 years ago