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Triss [41]
3 years ago
5

What is the general equation of a sine function with an amplitude of 6, a period of startfraction pi over 4 endfraction, and a h

orizontal shift of startfraction pi over 2 endfraction?
Mathematics
1 answer:
natta225 [31]3 years ago
5 0

Answer:

  f(x) = 6·sin(8(x -π/2))

Step-by-step explanation:

A transformed sine function with amplitude A, period P, and horizontal shift S can be written as ...

  f(x) = A·sin(2π/P(x -S))

__

The equation for A=6, P=π/4, and S=π/2 is then ...

  f(x) = 6·sin(8(x -π/2))

_____

<em>Additional comment</em>

The horizontal shift is equal to two full periods, so the shifted function is indistinguishable from the unshifted function.

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A store employes 11 women and 12 men. What percentage of employes are men?
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20 POINTS PLS HELP
liraira [26]

Answer:

True answers for data in the plot are

The center is 13

The center is not 14

The Peak is 14.

It has three clusters

It is not symmetric to left or right it is bi-modal.

It is has a range from 10 to 15 most number of data points are 13 to 15.

Total number times Shelly waited is 16 times.

Step-by-step explanation:

While taking cumulative frequency 56.75 percentage comes in 13%.

It is the center point of the data.

The 14  is not the center as it shows 93rd percent.

It has three clusters 0-2 has one cluster,2-4 has 2nd cluster,5-8 third.

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4 years ago
Determine algebraically whether the function is even, odd, or neither even nor odd. f as a function of x is equal to x plus quan
xenn [34]

Answer:

1) Even for first problem.

2) Neither for the second.

I really think the problem I labeled 1 is the correct interpretation but just in case you meant the latter I wrote the latter as well. The sentence translates to exactly what I have for problem number 1.

The Problem:

1) Determine if f(x)=x+\frac{4}{x} is even, odd, or neither.

2) Determine if f(x)=\frac{x+4}{x} is even, odd, or neither.

Step-by-step explanation:

f(-x)=f(x) implies f is even.

f(-x)=-f(x) implies f is odd.

So either definition says we have to plug in -x.

1)

f(x)=x+\frac{4}{x} with new input -x:

f(-x)=-x+\frac{4}{-x}

f(-x)=-x+-\frac{4}{x}

f(-x)=-(x+\frac{4}{x})

f(-x)=-f(x)

This means f is even since we got the same thing we started with.

2)

f(x)=\frac{x+4}{x} with new input -x:

f(-x)=\frac{-x+4}{-x}

f(-x)=\frac{-(x-4)}{-x}

f(-x)=\frac{x-4}{x}

This is neither the same or the opposite of what we started with.

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