It means not to get too invested in details or to become so invested in something that you can’t focus on anything else.
Answer:
m<TVZ = 95
Step-by-step explanation:
2x+15+2x+5= 180
4x+20 =180
-20 -20
4x=160
x= 40
2x+15= m<TVZ
2(40)+15 = m<TVZ
80+15 = m<TVZ
95 = m<TVZ
To check:
2x+5= <WVZ
2(40)+5 = <WVZ
80+5 = <WZV
85+95 = 180
The two angles together should equal 180. Comment if you have any questions :)
The equation that the clerk can use to calculate their total bill is t + g.
<h3>How to illustrate the equation?</h3>
From the information given, Yasuda family bought a toy that cost t dollars and a game that cost g dollars.
The equation to calculate their total bills will be:
= t + g
where,
t = cost of toy
g = cost of game.
In this case, the equation that the clerk can use to calculate their total bill is t + g .
Learn more about equations on:
brainly.com/question/2972832
#SPJ1
Answer:
Step-by-step explanation:
Area of an equilateral triangle = 
Sub in your value of 16ft
A = 
A = 110.85 
Answer:
The answer is "
"
Step-by-step explanation:
Given value:

Find:
area=?
calculation:

