3 years ago

Please help ASAP

2 answers:

8 0

Q(-6,4), p(-3,-8), and r(1,-1)

3 0

(-6, 4), (-3, -8), and( 1, -1)

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3 years ago

vlada-n [284]

Answer: $k^4+10k^3+21k^2$

Step-by-step explanation:

Given

Height of rectangle is $h=k^2+3k$

Width is $w=k^2+7k$

The area of the rectangle is given by the multiplication of the height and width

$\Rightarrow A=\left(k^2+3k\right)\left(k^2+7k\right)\\\\\Rightarrow A=k^2k^2+k^2\cdot \:7k+3kk^2+3k\cdot \:7k\\\\\Rightarrow A=k^4+10k^3+21k^2$

Thus, the area of the rectangle is $k^4+10k^3+21k^2$ .

3 0

3 years ago