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2 years ago

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Reagan used 1,297 sq ft of wrapping paper to wrap gifts for everyone in her class. If each gift used the same amount of wrapping

paper and she wrapped 24 gifts, how much wrapping paper did she use for each gift?

1 answer:

seraphim [82]2 years ago

5 0

She used 54.04 sq ft of wrapping paper

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Sara has $65 and wants to buy the following items from a store. Board game: $14.95 Building blocks: $25.49 Art kit: $35.79 At th

valina [46]

The correct statement is Sara can afford to purchase the items because the final price of the items is $60.

The first step is to determine the total cost of the items Sara wants to buy. The total cost can be determined by adding the cost of the items together.

Total cost = $14.95 + $25.49 + $35.79 = $76.23

The second step is to determine the cost of the items after the discount.

Price of the items = total cost x (1 - discount)

= total cost x (1 - 1/4)

total cost x 3/4

$76.23 x 3/4 = $57.17

The third step is to determine the cost of the items after tax.

Cost = (1.05) x $57.17 =$60.03

Please find attached the complete question. To learn more about taxes, please check: brainly.com/question/25311567

4 0

1 year ago

Find the area of the surface. The part of the surface z = xy that lies within the cylinder x2 + y2 = 36.

rewona [7]

Answer:

Step-by-step explanation:

From the given information:

The domain D of integration in polar coordinates can be represented by:

D = {(r,θ)| 0 ≤ r ≤ 6, 0 ≤ θ ≤ 2π) &;

The partial derivates for z = xy can be expressed as:

$y =\dfrac{\partial z}{\partial x} , x = \dfrac{\partial z}{\partial y}$

Thus, the area of the surface is as follows:

$\iint_D \sqrt{(\dfrac{\partial z}{\partial x})^2+ (\dfrac{\partial z}{\partial y})^2 +1 }\ dA = \iint_D \sqrt{(y)^2+(x)^2+1 } \ dA$

$= \iint_D \sqrt{x^2 +y^2 +1 } \ dA$

$= \int^{2 \pi}_{0} \int^{6}_{0} \ r \sqrt{r^2 +1 } \ dr \ d \theta$

$=2 \pi \int^{6}_{0} \ r \sqrt{r^2 +1 } \ dr$

$= 2 \pi \begin {bmatrix} \dfrac{1}{3}(r^2 +1) ^{^\dfrac{3}{2}} \end {bmatrix}^6_0$

$= 2 \pi \times \dfrac{1}{3} \Bigg [ (37)^{3/2} - 1 \Bigg]$

$= \dfrac{2 \pi}{3} \Bigg [37 \sqrt{37} -1 \Bigg ]$

3 0

2 years ago

For the equation y = - 3x + 2 2. determine the value of y when x = 2?

sergejj [24]

Y = -3(2) +22
Y = -6 +22
Y = 16

8 0

2 years ago

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Helpppppp 50 pointssss

djyliett [7]

Answer:

A

Step-by-step explanation:

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2 years ago

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What expressions equal to 19

svp [43]

19 = 19/1 = 38/2 = 57/3 = 76/4

3 0

3 years ago