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photoshop1234 [79]
3 years ago
14

If you buy a package then you get a 12% discount The discounted price is $132. What is the price of the package without the disc

ount.
Mathematics
1 answer:
lianna [129]3 years ago
8 0
12% of $132=15.84

$132+15.84

=$147.84


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Solve the system of equations using elimination<br> x-y=3<br> 2x+2y=50
pishuonlain [190]

Answer:

X=14

Y=11

Step-by-step explanation:

14-11=3

14x2=28

11x2=22

22+28=50

Hope that works :)

6 0
2 years ago
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Please help me answer this for a test im having trouble
Dimas [21]

Answer:

x + 1

y = 9

Step-by-step explanation:

In order to solve this question we need to represent "y "in terms of "x" in the first equation, and the plug in the "y" value in the first equation into the second one. Luckily for us in the first equation it already shows what "y" is equal to in terms of "x" (based on the first equation y = -x + 10). Now we just need to plug in the value that we got instead of "y" in the second equation, and so we get....

y = 7x + 2

(plug in the y value and get the following ….)

-x + 10 = 7x + 2

(now just solve the following equation)

-x + 10 + x = 7x + 2 + x

10 = 8x + 2

10 - 2 = 8x + 2 - 2

8 = 8x

8/8 = 8x/8

1 = x

Now that we know the value of "x", all we need to do now is substitute the value of "x" into any of the equations and we will get the value of "y". So we do the following.....

y =  7x + 2

y = 7(1) + 2

y = 7 + 2

y = 9

3 0
3 years ago
Draco Malfoy or the Weasley twins?
tekilochka [14]

Answer:

DRACO MALFOY FOR SURE

Step-by-step explanation:

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2 years ago
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Plsss helppp I’m dying!! —&gt; Complete the square to determine if the equation is a circle, quadratic equation, or other
sashaice [31]

a) The equation represents an ellipse.

b) The equation represents a circle.

c) The equation represents a parabola.

<h3>How to infer the graphical form of a general equation</h3>

In this problem we have <em>general</em> equations of the form A · x² + B · y² + C · x + D · y + E = 0, which have to be modified into <em>standard</em> form to infer its <em>graphical</em> form. This procedure can be done by <em>algebra</em> properties:

16 · x² + 4 · y² + 96 · x - 8 · y + 84 = 0

[(4 · x)² + 2 · 12 · (4 · x)] + [(2 · y)² - 2 · 2 · (2 · y)] = - 84

[(4 · x)² + 2 · 12 · (4 · x) + 144] + [(2 · y)² - 2 · 2 · (2 · y) + 4] = 64

(4 · x + 12)² + (2 · y + 2)² = 64

4² · (x + 3)² + 2² · (y + 2)² = 64

(x + 3)² / 4 + (y + 2)² / 16 = 1 : Ellipse

x² + y² + 8 · x - 6 · y - 15 = 0

(x² + 8 · x) + (y² - 6 · y) = 15

(x² + 2 · 4 · x + 16) + (y² - 2 · 3 · y + 9) = 40

(x + 4)² + (y - 3)² = 40 : Circle

x² + 6 · x + 4 · y + 5 = 0

x² + 6 · x + 5 = - 4 · y

y = - (1 / 4) · x² - (3 / 2) · x - (5 / 4) : Parabola

To learn more on ellipses: brainly.com/question/19507943

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1 year ago
What is the inverse of the function
Evgesh-ka [11]

Answer:

A

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = \frac{19}{x^3} ( multiply both sides by x³ )

x³y = 19 ( divide both sides by y )

x³ = \frac{19}{y} ( take the cube root of both sides )

x = \sqrt[3]{\frac{19}{y} }

Change y back into terms of x, then

f^{-1} (x) = \sqrt[3]{\frac{19}{x} } = \frac{\sqrt[3]{19} }{\sqrt[3]{x} } → A

6 0
3 years ago
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