Answer:
no solutions exist
Step-by-step explanation:
You can rewrite the denominator as:
-2(2x-6) so the equation becomes:
from which you can see that not only should x ≠ 3, but for all values of x≠3 the equation is false.
YOU KNOW THAT THE SUM OF THE ANGLES IN A QUADRILATERAL IS 360 DECREES. HOW CAN THIS HELP YOU REMEMBER THAT THE SUM OF THE ANGLES
1 answer:
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Answer:
14 and 16.
Step-by-step explanation:
We know that two consecutive even numbers is 30.
Let's let n be <em>any number</em>.
Then the first <em>even</em> number must be 2n.
This is because n can be any number, either even or odd. However, if we multiply it by 2, this <em>ensures</em> that 2n is even. Remember that any number multiplied by 2 yields an even number.
Therefore, the consecutive even number will be (2n+2). Not (2n+1), because that gives an odd number.
We know that they sum to 30. So, we can write the following equation.
And we solve from there:
So, the value of n is 7.
Therefore, the first even number is 7(2)=14.
And the consecutive even number is 16.
Edit: Typo
Answer:
Now we can calculate the p value with this probability:
If we use a significance level os 0.05 we see that the p value is lower than the significance level so then we can conclude that the true proportion of students with jobs is higher than 0.35 for this case. If we decrease the significance level to 1% the result changes otherwise not.
Step-by-step explanation:
Information given
n=78 represent the random sample taken
X=36 represent the students with jobs
estimated proportion of students with jobs
is the value that we want to test
z would represent the statistic
represent the p value
Hypothesis to test
We want to test if the proportion of students with jobs is higher than 0.35, the system of hypothesis are:
Null hypothesis:
Alternative hypothesis:
The statistic is given by:
(1)
Replacing the info we got:
Now we can calculate the p value with this probability:
If we use a significance level os 0.05 we see that the p value is lower than the significance level so then we can conclude that the true proportion of students with jobs is higher than 0.35 for this case. If we decrease the significance level to 1% the result changes otherwise not.