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marissa [1.9K]
3 years ago
9

Sharon has a patio in the shape of a rectangle

Mathematics
1 answer:
sdas [7]3 years ago
8 0

Answer:

D

Step-by-step explanation:

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Given the function f(x), what is the transformation f(x-r), is a real number and r>0?
anastassius [24]

Answer:

0 - r = the graph shifts r units left

Step-by-step explanation:

When you have 2 x intercepts of 0, -r then you shift left to negative

8 0
3 years ago
How do I solve this? ​
Ainat [17]

Answer:

pythagoren therom, law of sine, cosine, and tangent

Step-by-step explanation:

6 0
3 years ago
Which of the following is an identity? Also, please include an explanation.
Lerok [7]
cot\theta= \frac{ cos \theta}{ sin \theta } \\ sec\theta = \frac{1}{ cos \theta } \\ \\  \\ sin \theta cot\theta sec\theta \\ = sin \theta \cdot \frac{ cos \theta}{ sin \theta } \cdot \frac{1}{ cos \theta } \\ = \frac{ sin \theta}{ sin \theta } =1 \\


sinθcotθsecθ = 1





6 0
4 years ago
Expand (2 + a)9 using Pascal’s triangle.
Natalija [7]

Answer:

Step-by-step explanation:

The Pascal triangle is used to determine the coefficients of the terms when we expand the expression.

                                             1                                (A + B) ^ 0 = 1

                                         1       1                            (A +B ) ^ 1 = 1A + 1B

                                   1          2        1          (A+ B) ^ 2 = 1A^2 + 2 AB + 1B^2

By extending the triangle, you will get the 9th row, which is your expression, of the coefficients. that is

1          9       36    84    126    126    84    36    9    1

Now, fill in AB in the gaps.

1AB + 9 AB + 36AB + 84AB + 126AB + 126AB +84AB + 36AB + 9AB + 1AB

Next, you need to go from the left to fill out the exponent of A and it will go down from 9 (the exponent of the whole thing) . That is

1A^9B+9A^8B+36A^7B+84A^6B+126A^5B+126A^4B+84A^3B+36A^2B+9A^1B+1A^0B

Next will be the exponent of B. this time, you go from the right and do the same with A. You can go from the left also, but go up from 0 to 9 for the exponent of B

1A^9B^0+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+1A^0B^9

The last step is just to simplify the A^0=1 and B^0 =1 at the first and the last terms.

A^9+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+B^9

Hope you can learn the method

5 0
3 years ago
Round the following numbers to the nearest 10<br> a) 83<br> b) 127<br> c) 245
dolphi86 [110]
I believe the answer is-
a) 80
b) 130
c) 250
5 0
3 years ago
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