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nordsb [41]
2 years ago
10

What expression can be used to add 3/4 + 1/6

Mathematics
1 answer:
saveliy_v [14]2 years ago
5 0

Answer:

11 / 12 or 0.9167

Step-by-step explanation:

Given:

3/4 + 1/6

Find:

Value with expression

Computation:

"3/4 added to number 1/6"

3/4 + 1/6

By taking LCM

[9 + 2] / 12

11 / 12 or 0.9167

brainliest?

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Sahil chooses a number, divides it by 8 , adds 8 to the answer. Then multiples the answer with 8 . He obtains the result as 952
babunello [35]

Answer:

888

Step-by-step explanation:

Sahil chooses a number, [We'll call it x]

divides it by 8 ,   [x/8]

adds 8 to the answer.  [(x/8) + 8]

Then multiples the answer with 8 .  [((x/8) + 8)*8]

He obtains the result as 952 .   [((x/8) + 8)*8 = 952]

The number he chooses in the beginning was

((x/8) + 8)*8 = 952

x + 64 = 952

x = 888

CHECK:

Does (888/8 + 8)*8 = 952?

(119)*8 = 952?   YES

The number is 888

8 0
3 years ago
Estimate: 25.73 – 2.19<br> 24<br> 22<br> 25<br> 23
dalvyx [7]

Answer:

23

Step-by-step explanation:

25.73−2.19

=25.73−2.19

=25.73+−2.19

=23.54

8 0
3 years ago
Read 2 more answers
A quadratic function f(x)f(x) is hidden from view. You must find the xx-intercept(s) of f(x)f(x) and write the answer(s) in the
Alika [10]

f(x) should be in canonical form. So it must have the form

f(x)=a(x-x_v)^2+y_v

Where a is the main coefficient and is the vertex

Step-by-step explanation:

A quadratic function has a unique extreme value in its vertex. That value might be a maximum or a minimum depending on the sign of the main coefficient of the quadratic function. In order to quickly obtain the vertex, the quadratic must be written in canonical form. That means that f(x) must have the form

f(x)=a(x-x_v)^2+y_v

Where a is the main coefficient (which should be negative so that a minimum exists in the first place) and is the vertex. If f(x) is written in that form, then it will be easier to find the minimum of f(x), which is the vertex

Hence for the quadratic function below

\begin{gathered} f(x)=(x-2)^2-9 \\ f(x)=x^2-4x-5 \\ ax^2+bx+c \\ a=1,\text{ b=-4, c=-5} \\ x_v=-\frac{b}{2a} \\ x_v=\frac{-(-4)}{2(1)} \\ x_v=\frac{4}{2} \\ x_v=2 \\ y_v=2^2-4(2)-5 \\ y_v=-9 \\ (x,y)\longrightarrow(2,-9) \end{gathered}

Hence there is only one x- intercept and answer is (2, -9)

7 0
2 years ago
(5×10^– 2)(1×10^– 8)
Citrus2011 [14]

Answer:

5e-10

Step-by-step explanation:

Hope this will help

7 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST!!!!!!! Use graphs and tables to find the limit and identify any vertical asymptotes of the function. limit
garri49 [273]

Answer:

see below

Step-by-step explanation:

lim x/ (x-4)

as x approaches 4 from the left

let x = 3.9

3.9/ (3.9-4) = -39

Let x = 3.99

3.99/ (3.99 - 4) =-399

As we get closer to 4 from the left we get larger and larger so we will get closer to - negative infinity

The limit as shown in the graph is negative infinity

The vertical asymptote is x=4

The horizontal symptote is y =1

8 0
4 years ago
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