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mina [271]
3 years ago
5

Find the GCF of 36 and 42

Mathematics
1 answer:
8_murik_8 [283]3 years ago
3 0

Answer:

the GCF of 36 and 42 is 6

Step-by-step explanation:

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Next number in sequence 3 -6 12 4 20 ?
Artyom0805 [142]
-6 - 3 = -9
12 - (-6) = 18
4 - 12 = -8
20 - 4 = 16
The first difference is -9. The third difference is -8.
Maybe the fifth difference is -7.
That makes the next term 13.

<span>3, -6, 12, 4, 20, 13</span>
8 0
3 years ago
Which system is equivalent to the system shown and could be used to solve the system of equations correctly using the eliminatio
Bumek [7]

Answer:

The solution is (2, -2)

Step-by-step explanation:

In order to solve this, multiply the second equation by -5 and then add through.

5x - 4y = 18

-5x - 15y = 20

------------------

-19y = 38

y = -2

Now that we have the value of y, we can solve for x.

x + 3y = -4

x + 3(-2) = -4

x - 6 = -4

x = 2

5 0
3 years ago
If three times a number minus 2 equals 13, what is the number?
Nana76 [90]
Change the messy words into numerals
3     times          a number         minus            2           equals         13
3          ×                n                     -                 2               =               13

3n - 2 = 13
take 2 to the other side
3n - 2 + (2)  = 13 + (2)
3n = 15

Divide by 3 on either sides to isolate n
\frac{3n}{3} = \frac{15}{3}
3 and 3 cancels out

n = 5

check:
3 times 5 minus 2 equals 13
3     ×    5       -      2     =     13
15    -      2        =          13
13            =               13

The number is 5
3 0
3 years ago
Simplify the expression. –9z – 13z 4 22z –22z 4z
Sloan [31]
Answer
-22z
Explanation:
3 0
4 years ago
Dada la ecuacion 25x2 + 4y2 = 100, determina las coordenadas de los vertices, focos, las longitudes de los respectivos ejes mayo
Likurg_2 [28]

Answer:

The given equation is

25x^{2} +4y^{2}=100

Which represents an elipse.

To find its elements, we need to divide the equation by 100

\frac{25x^{2} +4y^{2} }{100} =\frac{100}{100} \\\frac{x^{2} }{4} +\frac{y^{2} }{25} =1

Where a^{2} =25 and b^{2}=4. Remember that the greatest denominator is a, and the least is b. So, we extract the square root on each equation.

a=5 and b=2.

In a elipse, we have a major axis and a minor axis. In this case, the major axis is vertical and the minor axis is horizontal, that means this is a vertical elipse.

The length of the major axis is 2a=2(5)=10.

The length of the minor axis is 2b=2(2)=4.

The vertices are (0,5);(0,-5) and (2,0);(-2,0).

Now, the main parameters of an elipse are related by

a^{2}=b^{2} +c^{2}, which we are gonna use to find c, the parameter of the focus.

c=\sqrt{a^{2}-b^{2} }=\sqrt{25-4}=\sqrt{21}

So, the coordinates of each focus are (0,\sqrt{21}) and (0,-\sqrt{21})

The eccentricity of a elipse is defined

e=\frac{c}{a}=\frac{\sqrt{21} }{5}  \approx 0.92

The latus rectum is defined

L=\frac{2b^{2} }{a}=\frac{2(4)}{5} =\frac{8}{5} \approx 1.6

Finally, the graph of the elipse is attached.

7 0
3 years ago
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