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2 years ago

Quick Question! Please help!

Mathematics

2 answers:

alisha [4.7K]2 years ago

6 0

When the power on a variable inside the bracket becomes the same the powers are added.

Have a look at the attachment.

8090 [49]2 years ago

3 0

Answer:

C --- b^16

Step-by-step explanation:

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Jemma is three times as old as Angie. Five years from now the sum of their ages will be 34 years. What are their present ages?

Lapatulllka [165]

Answer: Angie = 6, Jemma = 18

Step-by-step explanation:

Let x represent the current age of Angie

Current Age Age 5 years from now

Angie: x x + 5

Jemma: 3x 3x + 5

5 years from now the sum of their ages is 34

(x + 5) + (3x + 5) = 34

4x + 10 = 34

4x = 24

x = 6

Angle's current age is x = 6

Jemma's current age is 3x = 3(6) = 18

5 0

3 years ago

Read 2 more answers

In the linear equation y = 4x + 2, the value 2 represents which of the following?

Rzqust [24]

The answer is B: the y-coordinate of the y int.

5 0

2 years ago

(calculus) please help!! will mark brainliest

Lyrx [107]

Answer:

Step-by-step explanation:

4 0

2 years ago

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

8 0

3 years ago

Homework Progress 0 Find the nth term of the following sequence: 4 7 12 19 28

just olya [345]

Answer:

n²+3

Explanation:

The differences between the terms are not the same, so this is not "linear". Knowing that the sequence may have started with a 1, you can try subtracting the first number with a number to get 1, and use that number to subtract the rest.

4 - 3 = 1
7 - 3 = 4
12 - 3 = 9
19 - 3 = 16
28 - 3 = 25

In this case, subtracting 3 to all the numbers gave us perfect squares! So this means the nth term has to do with squaring the number and adding three afterward! This can be checked.

√1 = 1
√4 = 2
√9 = 3
√16 = 4
√25 = 5

As we found the values of these terms by subtracting three first and then finding its square root, the nth term will be the opposite; squaring and then adding three! Again, this can be checked!

1² + 3 = 4
2² + 3 = 7
3² + 3 = 12
4² + 3 = 19
5² + 3 = 28

Hope this helps !! :D

5 0

1 year ago