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3 years ago

About 1 liter of water is left in this water cooler. What is the best estimate of how much water in the cooler when it was full

Mathematics

1 answer:

svetlana [45]3 years ago

6 0

Answer:

18.9 I THINK

Step-by-step explanation:

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-24 - (-6) = -24 + 6 True or False.

abruzzese [7]

Answer:

True

Step-by-step explanation:

When you have 2 negative together they will become a positive (5- (-2) = 7)

5 0

2 years ago

Read 2 more answers

Find the area of the shape.

DedPeter [7]

Step by step: Here,

Formula to find area=l×b

=(2x+3)×(x+4)

=6x × 4x

=24x

Or,

2x+3 × x+4

2xsquare+7

4 0

3 years ago

Write y+1=5/2(x-2)+2 in standard form step by step please

Elden [556K]

Answer: 5x - 2y = 8

y+1=5/2(x-2)+2

multiply the each side by 2 to get rid of the fraction

2 (y+1) = (5/2 (x-2) +2 )2

2y+2=5(x-2)+4

now distribute the 5

2y+2=5x-10+4

subtract the two from each side

2y=5x-10+4-2

add like terms

2y=5x-8

subtract 5x from each side

2y-5x=-8

multiple the whole equation by -1 to make the 5x a positive

-2y+5x=8

hope this helps!

6 0

2 years ago

What is the square root of -2i?

Studentka2010 [4]

Answer:

1-i and -1+i

Step-by-step explanation:

We are to find the square roots of $z=0-2i$ . First, convert from Cartesian to polar form:

$r=\sqrt{a^2+b^2}\\r=\sqrt{0^2+(-2)^2}\\r=\sqrt{0+4}\\r=\sqrt{4}\\r=2$

$\theta=tan^{-1}(\frac{b}{a})\\ \theta=tan^{-1}(\frac{-2}{0})\\\theta=\frac{3\pi}{2}$

$z=2(\cos\frac{3\pi}{2}+i\sin\frac{3\pi}{2})$

Next, use the formula $\displaystyle \sqrt[n]{r}\biggr[\cis\biggr(\frac{\theta+2\pi k}{n}\biggr)\biggr]$ where $\displaystyle k=0,1,2,...\:,n-1$ to find the square roots:

When k=1

$\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(1)}{2}\biggr)\biggr]$

$\displaystyle \sqrt{2}\biggr[cis\biggr(\frac{3\pi}{4}+\pi\biggr)\biggr]$

$\sqrt{2}\biggr(cis\frac{7\pi}{4}\biggr)$

$\sqrt{2}(\cos\frac{7\pi}{4}+i\sin\frac{7\pi}{4})\\ \\\sqrt{2}(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i)\\ \\1-i$

When k=0

$\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(0)}{2}\biggr)\biggr]$

$\sqrt{2}\biggr(cis\frac{3\pi}{4}\biggr)$

$\sqrt{2}(\cos\frac{3\pi}{4}+i\sin\frac{3\pi}{4})\\ \\\sqrt{2}(-\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}i)\\ \\-1+i$

Thus, the square roots of -2i are 1-i and -1+i

4 0

2 years ago

How many solutions are there to the equation below?

Effectus [21]

Answer:

C. 1

Step-by-step explanation:

Given:

$\displaystyle \large{\sqrt{\sqrt{\sqrt{x}}} = 16}$

The equation can be rewritten as:

$\displaystyle \large{\sqrt[8]{x} = 16}$ via surd property.

Since it’s an even surd, that means there only exists zero-positive numbers for value of x.

To solve this surd equation, simply clear out the surd by powering both sides by 8:

$\displaystyle \large{\left(\sqrt[8]{x}\right )^8=(16)^8}$

Cancel the surd:

$\displaystyle \large{x=16^8}$

Now, evaluating 16^8 will give up a million and that’s not necessary because we are finding how many solutions this equation has. Since theee only exists one value of x, which is the solution to this equation. Therefore:

Your answer is 1 solution

4 0

2 years ago