means to say that for any given 
, we can find 
such that anytime 
(i.e. the whenever 
is "close enough" to 5), we can guarantee that 
(i.e. the value of 
is "close enough" to the limit value).
What we want to end up with is
Dividing both sides by 3 gives
which suggests 
is a sufficient threshold.
The proof itself is essentially the reverse of this analysis: Let be given. Then if
and so the limit is 7. QED
True... is there any specific to your question?
Distribute the 2
2x-8=8
Add 8 to both sides
2x=16
divide by two
x=8
divide number of students in sports by percentage:
372 / 0.60 = 620 total students in the school
Answer:
8
Step-by-step explanation:
5 x 6 = 30
6 x 6 = 36
8 x 6 = 48
