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Marizza181 [45]
3 years ago
10

13d+8=-1 b=? need answer

Mathematics
2 answers:
Harrizon [31]3 years ago
7 0

Answer:

d=\frac{-9}{13}

Step-by-step explanation:

Original equation: 13d+8=-1

1. Subtract 8 from both sides of the equation to get:

13d=-9

2. Divide both sides by 13 to get:

d=\frac{-9}{13}

In-s [12.5K]3 years ago
7 0

Answer:

-9/13

Step-by-step explanation:

i took the iready quiz

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Find the two square roots of each complex number by creating and solving polynomial equations.
son4ous [18]

Answer:

1) w₁=4 - i w₂= -4 + i

2) w₁= 3 - i w₂= -3  + i

3) w₁= 1 + 2i w₂= - 1 - 2i

4) w₁= 2- 3i w₂= -2 + 3i

5) w₁= 5 - 2i w₂= -5 + 2i

6) w₁= 5 - 3i w₂= -5 + 3i

Step-by-step explanation:

The root of a complex number is given by:

\sqrt[n]{z}=\sqrt[n]{r}(Cos(\frac{\theta+2k\pi}{n}) + i Sin(\frac{\theta+2k\pi}{n}))

where:

r: is the module of the complex number

θ: is the angle of the complex number to the positive axis x

n: index of the root

1) z = 15 − 8i  ⇒ r=17 θ= -0.4899 rad

w₁=\sqrt{17}(Cos(\frac{-0.4899}{2}) + i Sin(\frac{-0.4899}{2}))=4-i

w₂=\sqrt{17}(Cos(\frac{-0.4899+2\pi}{2}) + i Sin(\frac{-0.4899+2\pi}{2}))=-1+i

2) z = 8 − 6i  ⇒ r=10 θ= -0.6435 rad

w₁=\sqrt{10}(Cos(\frac{ -0.6435}{2}) + i Sin(\frac{ -0.6435}{2}))= 3 - i

w₂=\sqrt{10}(Cos(\frac{ -0.6435+2\pi}{2}) + i Sin(\frac{ -0.6435+2\pi}{2}))= -3  + i

3) z = −3 + 4i  ⇒ r=5 θ= -0.9316 rad

w₁=\sqrt{5}(Cos(\frac{-0.9316}{2}) + i Sin(\frac{-0.9316}{2}))= 1 + 2i

w₂=\sqrt{5}(Cos(\frac{-0.9316+2\pi}{2}) + i Sin(\frac{-0.9316+2\pi}{2}))= -1 - 2i

4) z = −5 − 12i  ⇒ r=13 θ= 0.4426 rad

w₁=\sqrt{13}(Cos(\frac{0.4426}{2}) + i Sin(\frac{0.4426}{2}))= 2- 3i

w₂=\sqrt{13}(Cos(\frac{0.4426+2\pi}{2}) + i Sin(\frac{0.4426+2\pi}{2}))= -2 + 3i

5) z = 21 − 20i  ⇒ r=29 θ= -0.8098 rad

w₁=\sqrt{29}(Cos(\frac{-0.8098}{2}) + i Sin(\frac{-0.8098}{2}))= 5 - 2i

w₂=\sqrt{29}(Cos(\frac{-0.8098+2\pi}{2}) + i Sin(\frac{-0.8098+2\pi}{2}))= -5 + 2i

6) z = 16 − 30i ⇒ r=34 θ= -1.0808 rad

w₁=\sqrt{34}(Cos(\frac{-1.0808}{2}) + i Sin(\frac{-1.0808}{2}))= 5 - 3i

w₂=\sqrt{34}(Cos(\frac{-1.0808+2\pi}{2}) + i Sin(\frac{-1.0808+2\pi}{2}))= -5 + 3i

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4 years ago
64 POINTS AWARDED, PLEASE ANSWER ASAP!!!!!
antoniya [11.8K]

Answer:

Area of rectangle = 40 square units

Step-by-step explanation:

<u>Points to remember</u>

<u>Distance formula</u>

Length of a line segment with end points (x₁, y₁) and (x₂, y₂) is given by,

Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

Area of rectangle = Length * Breadth

<u>To find the length and breadth</u>

Here a rectangle with vertices at (7, 3), (12, 3), (12, 11), and (7, 11)

Length1 =  √[(x₂ - x₁)² + (y₂ - y₁)²]

√[(12 - 7)² + (3 - 3)²] = √5² = 5

Length2 =  √[(x₂ - x₁)² + (y₂ - y₁)²]

√[(12 - 12)² + (11 - 3)²] = √8² = 8 units

Therefore Length of rectangle = 8 and  

Breadth of rectangle = 5 units

<u>To find the area of rectangle</u>

Area = Length * Breadth

  = 8 * 5 =  40 square units

8 0
3 years ago
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In a game of pool, a 0.4 kg cue ball is traveling at 0.80 m/s when it hits a slower striped ball moving at 0.38 m/s. after the c
LiRa [457]

The magnitude of the final velocity of the cue ball is (B) 0.56m/s.

<h3>What is Velocity</h3>
  • The definition of velocity is a vector measurement of the rate and direction of motion.
  • It is a moving body's speed and direction of motion.

How to calculate the magnitude of the final velocity?

The magnitude of the final velocity can be calculated by following the steps:

  • The mass of the cue ball given is 0.4kg.
  • The velocity of the cue ball given is +0.80m/s.
  • The velocity of the striped ball before the collision is +0.38 m/s.
  • The velocity of the striped ball after collision is +0.62m/s.
  • We need to find the magnitude of the final velocity of the cue ball.

Assuming all pool balls have the same mass: 0.4kg

Let the final velocity of the cue ball be x.

Now, To find the final velocity:

  • Mass of the cue ball × initial velocity of cue ball + Mass of striped ball + initial velocity of striped ball = mass of cue ball × final velocity + mass of striped ball × final velocity of the striped ball

  • (0.40)×(0.80)+(0.4)(0.38) = (0.4)(x)+(0.4)(0.62)
  • 0.32+0.152=0.4x+0.248
  • 0.472=0.4x+0.248
  • 0.472-0.248= 0.4x
  • 0.224/0.4 =x
  • x = 0.56m/s

Therefore, the magnitude of the final velocity of the cue ball is (B) 0.56m/s.

Know more about velocity here:

brainly.com/question/25749514

#SPJ4

The correct question is given below:

In a game of pool, a 0.4 kg cue ball is traveling at +0.80 m/s when it hits a slower striped ball moving at +0.38 m/s. After the collision, the striped ball moves off at +0.62 m/s. What is the magnitude of the final velocity of the cue ball? Assume all pool balls have the same mass.

A. 0.20 m/s

B. 0.56 m/s

C. 1.0 m/s

D. 1.8 m/s

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AleksAgata [21]
5.C
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6 0
3 years ago
Select all ratios equivalent to 30:6
Korolek [52]

Answer:

60 : 12

90 : 18

120 : 24

150 : 30

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