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vovangra [49]
2 years ago
10

It is always helpful to rewrite a quadratic equation in standard form as a first step in solving it.

Mathematics
2 answers:
kotykmax [81]2 years ago
5 0
THE ANSWER IS (B) true
kifflom [539]2 years ago
5 0

Answer:

A

Step-by-step explanation:

Now when I think of solving it, I think of finding the zeros.  Now if you start with the form, for example:

(x+3)(x-3)

Then you can easily see the zeros are -3 and 3.

But if you start with the standard form:

ax^2+bx+c=0\\or\\x^2-9

It will be harder to find the zeros and you would do the eqation or factor it.

So if your in the factored form don't go to standard to find the zeros.

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What is the result of substituting for y in the bottom equation?<br> y=x-7<br> y=2+2x-4
Makovka662 [10]

Answer:

Plug x-7 in for y, in the bottom equation.

x - 7 = 2 + 2x - 4

x - 7 = 2x - 2

x = 2x + 5

-x = 5

x = -5

6 0
3 years ago
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Help me pleasee<br> Questions r in picture
jok3333 [9.3K]
<h2>Answer:</h2>

\large \bf\implies\frac{12}{61}

<h2>Step-by-step explanation:</h2>

<h2>Given :</h2>

\tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...

<h2>To Find :</h2>

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<h2>Solution :</h2>

We have to add 1 in numerator and -10 in denominator because

\tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...[Given]

\frac{8  \: + \:  1}{101 \:  - \:  10}  =  \frac{9}{91} \\\\  \frac{9 + 1}{91 - 10}  =  \frac{10}{81}  \\ \\ \frac{10 + 1}{81 - 10}  =  \frac{11}{71}  \\ \\ \frac{11 + 1}{71 - 10}  =  \frac{12}{61} ...

The difference is 1 in numerator so we add 1 and the difference is -10 in denominator so we subtract -10.

4 0
2 years ago
Find the solution(s) to 22 +57-3 = 0. Check all that apply.
irakobra [83]

Answer:

x = -3 and x = 1/2

Step-by-step explanation:

To find the solutions to

2x² + 5x - 3 = 0

we can use the quadratic formula, as follows:

x = \frac{-b \pm \sqrt{b^2- 4(a)(c)}}{2(a)}

x = \frac{-5 \pm \sqrt{5^2- 4(2)(-3)}}{2(2)}

x = \frac{-5 \pm 7}{4}

x_1 = \frac{-5 + 7}{4}

x_1 = 0.5

x_2 = \frac{-5 - 7}{4}

x_2 = -3

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