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vovangra [49]
2 years ago
10

It is always helpful to rewrite a quadratic equation in standard form as a first step in solving it.

Mathematics
2 answers:
kotykmax [81]2 years ago
5 0
THE ANSWER IS (B) true
kifflom [539]2 years ago
5 0

Answer:

A

Step-by-step explanation:

Now when I think of solving it, I think of finding the zeros.  Now if you start with the form, for example:

(x+3)(x-3)

Then you can easily see the zeros are -3 and 3.

But if you start with the standard form:

ax^2+bx+c=0\\or\\x^2-9

It will be harder to find the zeros and you would do the eqation or factor it.

So if your in the factored form don't go to standard to find the zeros.

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The function f(x) is a quadratic function and a limited table of values is provided below. Write the equation of the quadratic p
OverLord2011 [107]

Answer:

  f(x) = 3x^2 -21x +36

Step-by-step explanation:

The table gives the x- and y-intercepts, which are sufficient to write the equation in factored form. The x-intercepts of 3 and 4 tell you that factors are (x -3)(x -4). When x=0, this product is (-3)(-4) = 12, but the y-intercept value is 3 times that: 36. So, the factored equation is ...

  f(x) = 3(x -3)(x -4)

Multiplying this out, we get ...

  f(x) = 3(x^2 -7x +12)

  f(x) = 3x^2 -21x +36

4 0
3 years ago
Use the given data to construct a box plot and identify the 5-number summary. Eleven different second-year medical students at B
Galina-37 [17]

Answer:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

Step-by-step explanation:

We have the following data given:

130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150

If we sort the values on increasing order we got:

120 130 130 130 130 135 140 140 143 144 150

The minimum and maximum are:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

8 0
3 years ago
Is 5x^7 monomial? <br> please help :(
Reil [10]

Answer:

No, it is a binomial.

Step-by-step explanation:

8 0
3 years ago
Hi Brainly Community!
lana66690 [7]
I think x=6 then the equation would would work
4 0
2 years ago
a pool charges $4each visit or you can buy a membership. write and solve an inequality to find out many times a person should us
Lostsunrise [7]

Answer:

Step-by-step explanation:

Let the number of visits to a pool = n

Charges of n visits = Number of visits × Charges per visit

                               = n × $4

                               = 4n

Let the membership amount of the pool = $m

So the inequality showing that a membership is less expensive than paying each visit to the pool will be

4n > m

Now we divide the inequality by 4

n > \frac{m}{4}

Therefore, membership of the pool will be less expensive until number of visits to the pool is one fourth of the membership.

8 0
3 years ago
Read 2 more answers
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