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vovangra [49]
2 years ago
10

It is always helpful to rewrite a quadratic equation in standard form as a first step in solving it.

Mathematics
2 answers:
kotykmax [81]2 years ago
5 0
THE ANSWER IS (B) true
kifflom [539]2 years ago
5 0

Answer:

A

Step-by-step explanation:

Now when I think of solving it, I think of finding the zeros.  Now if you start with the form, for example:

(x+3)(x-3)

Then you can easily see the zeros are -3 and 3.

But if you start with the standard form:

ax^2+bx+c=0\\or\\x^2-9

It will be harder to find the zeros and you would do the eqation or factor it.

So if your in the factored form don't go to standard to find the zeros.

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31=4-9y I need help sorry
Drupady [299]

Answer:

y=-3

Step-by-step explanation:

31=4-9y

9y=4-31

9y=-27

y=-27/9

y=-3

8 0
3 years ago
What is the aswer ??????​
svet-max [94.6K]

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A prime numbers are numbers which have only two factor

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mixer [17]
The equation of the tangent line can be found using slope formula and fact that slope = dy/dx.

\frac{dy}{dx} = \frac{y - y_0}{x - x_0}

where (x0,y0) is point A ---> (0,-1)

Then rearrange equation into slope-intercept form:
y = \frac{dy}{dx}(x - 0) -1

Finally sub in x=0 into dy/dx to get slope at the point (0,-1)

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At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

Rounding up

A sample of 1068 is needed.

8 0
3 years ago
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