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Maslowich
3 years ago
13

What is the classification of the following triangle. scalene, isosceles, or right​

Mathematics
1 answer:
Minchanka [31]3 years ago
6 0

Answer:

scalene!!!

Step-by-step explanation:

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What is the solution to log Subscript 2 Baseline (9 x) minus log Subscript 2 Baseline 3 = 3
sdas [7]

The value of x is  \frac{8}{3}

 Explanation:

The expression is  \log _{2}(9 x)-\log _{2}(3)=3  

Adding  \log _{2}(3) to both sides of the equation,  we get,

\log _{2}(9 x)=3+\log _{2}(3)

Using log definition, if  \log _{a}(b)=c  then  b=a^{c} , we have,

 9 x=2^{3+\log _{2}(3)}

Using exponent rule, a^{b+c}=a^{b} a^{c},

9x=2^{\log _{2}(3)} \cdot 2^{3}

Simplifying, we have,

9x=3\cdot8\\9x=24

Dividing both sides by 9, we have,

x=\frac{24}{9}

Simplifying,

x=\frac{8}{3}

Thus, the value of x is \frac{8}{3}

5 0
4 years ago
What is 30% of ( ) equals 60, find the missing number.
mote1985 [20]
<u>Solution:</u>
Let us rewrite 30% as \frac{3}{10}. Let x be the missing number.

\frac{3}{10}(x) = 60 \\ x =  \frac{10}{3}(60) =  \frac{600}{3} = 200

and we are done. 

<u>Note:</u> You can do the same method by saying that 30% = 0.3 which would then show us that 60 divided by 0.3 is 200.


7 0
4 years ago
Please help me, I will give 29 points!
timofeeve [1]

Answer:

−0.8x+4.8y+16

Step-by-step explanation:

4(0.5x+2.5y−0.7x−1.3y+4)

=(4)(0.5x+2.5y+−0.7x+−1.3y+4)

=(4)(0.5x)+(4)(2.5y)+(4)(−0.7x)+(4)(−1.3y)+(4)(4)

=2x+10y−2.8x−5.2y+16

=−0.8x+4.8y+16

3 0
3 years ago
Error error error error error error error
disa [49]
What is the question to your problem?
4 0
3 years ago
The top and bottom margins of a poster are 8 cm and the side margins are each 6 cm. If the area of printed material on the poste
hammer [34]

Answer:

Dimensions of the poster

Width  29.10 cm

Height 38.80 cm

A(min) = 1129.08 cm²

Step-by-step explanation:

Printed area = 390 cm² = Ap

Lets call x and y dimensions of printed area

x   width

y   height

Then Ap = x*y    and

y = Ap/x    ⇒    y = 390/x

Then   total area of the poster is:

A(t)  = ( x  + 12 ) * ( y + 16 )         and   y = 390/x

A as a function of x

A(x) = ( x  + 12 ) * ( 390/x + 16 )   ⇒  A(x) = 390 + 16x + 4680/x + 192

A(x) = 582 + 16x + 4680/x     (1)

Taking derivatives

A´(x) =  16 - (4680/x²)         ⇒ A´(x)  =  0

[ 16x² -4680] /x² = 0     16x²- 4680 = 0    ⇒     x² = 4680/16

x = 17.10 cm        and    y = 390/x      y = 390/17.10      y = 22.80 cm

A(t) = ( 17.10 + 12 ) * ( 22.80 + 16 )

A(t) = 29.10 * 38.80

A(t) = 1129.08 cm²

If we substitute  in equation (1) the value of x  ( 17.10) we see A(x) > 0

Then there is a minimun at the point x = 17.10

4 0
4 years ago
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