Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Answer:
d. -0.301
h. 1.38
Step-by-step explanation:
Loga0.5 = loga2^-1
= -1(loga2)
= -1 (0.301)
= -0.301
Loga24 = loga(2^3 x 3)
= loga2^3 + loga3
= 3 (loga2) + loga3
= 3 (0.301) + (0.477)
= 1.38
Answer:.40 cents
Step-by-step explanation: divide the total cost by the amount of items you have.
Answer:
m<1 = 105°
m<2 = 75°
very simple explanation:
a and b are perpendicular. line t intersects these perpendicular lines. the given 75° is, in short, an intersect of a line, which is 180°. 75-180=105. angles 1 and 2 are duplicates of what is shown
First you distribute the six
-138>-36b+42
Then you subtract 42
-180>-36b
Next, you divide by -36 and since you are dividing by a negative, you turn the sign around
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