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LUCKY_DIMON [66]
3 years ago
13

A total of 937 people attended the play.

Mathematics
1 answer:
ra1l [238]3 years ago
4 0

Answer:

612 adults & 361 students

Step-by-step explanation:

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Find f(1/3) if f(n) =3n
hichkok12 [17]

Answer:

f(1/3) = 1

Step-by-step explanation:

Plug 1/3 in for n

f(1/3) = 3(1/3)

Now simplify

f(1/3) = 1                 {   3(1/3) = (3/1)(1/3) = 3/3 = 1   }

6 0
3 years ago
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Where is the orthocenter of a triangle with vertices at (-4,8) (-1,5) and (5,5)?
Mariulka [41]
(-4,-4)  Answer)   triangle vertex coordinates -4,8 | -1,5 | 5,5 orthocenter
5 0
3 years ago
A 3pack of boxes of juice costs 1.09. A 12 pack of boxes cost 4.49. A case of 24 boxes costs 8.78. Which is the best buy?Explain
Leona [35]
1.09÷3= .3633 each
4.49÷12= .37416 each
8.78÷24= .3658 each

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5 0
4 years ago
The greatest common factor (GCF) of x^3, x^7, x^9 is ?<br> Please help
solong [7]

Answer:

x^3

Step-by-step explanation:

Let the greatest common factor of a,b,c such that a,b,c \in\mathbb{Z} and they are not all equal to zero, d is the common divisor of a and b. Therefore, d \mid a and d \mid b

You can write

D(a) = \{d \in\mathbb{Z} : d \mid a\}

D(b) = \{d \in\mathbb{Z} : d \mid b\}

The greatest common factor of a,b is given as

D(a,b) = \{d \in\mathbb{Z} : d \mid a \text{ and } d \mid b\}

and

D(a, b) = D(a) \cap D(b)

This happens because D(a,b) is upper bounded because if a\neq 0 then d \leq |a|

for all d\in D(a, b). Therefore, the set D(a, b) has the greatest elements.

Taking x^3, x^7, x^9 such that x>0

You can note that x^7 = x^3 \cdot x^4 and x^9 = x^3 \cdot x^6 =  x^3 \cdot x^3 \cdot x^3

Therefore, the greatest common factor is x^3

Note: x^3 \cap x^7 \cap x^9 = x^3

6 0
3 years ago
Plz help me i need help its for a test i give brailies (:
Anarel [89]
C......................................
8 0
3 years ago
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