Answer:
120
Step-by-step explanation:
A: D: 10 ≤ b ≤ 12
R: 0 ≤ W(b) ≤ 120
B: D: 0 ≤ b ≤ 10
R: 12 ≤ W(b) ≤ 120
C: D: 0 ≤ b ≤ 120
R: 0 ≤ W(b) ≤ 10
D: D: 0 ≤ b ≤ 10
R: 0 ≤ W(b) ≤ 120
Answer:
10
Step-by-step explanation:
d = 10
For:
(X1, Y1) = (13, 2)
(X2, Y2) = (7, 10)
Distance Equation Solution:
d=(7−13)2+(10−2)2−−−−−−−−−−−−−−−−−√
d=(−6)2+(8)2−−−−−−−−−−√
d=36+64−−−−−−√
d=1–√00
d=10
Answer:
Step-by-step explanation:
We are told the school sold raffle tickets, and each ticket has a digit either 1, 2, or 3. The school also sold 2 tickets with the number 000.
Therefore we have the following raffle tickets:
123
132
213
231
312
321
000
000
From the given information, we can deduce that the school sold 8 tickets and only one ticket can contain the number arrangement of 123, but 000 appeared twice.
Probability of 123 to be picked=
1/8 => 0.125
Probability of 000 to be picked=
2/8 => 0.25
Since the probability of 000 to be picked is greater than 123, a ticket number of 000 is more likely to be picked
Change both fractions into improper fractions then subtract Ans=19/3 R 6 1/3
Answer:
he
Step-by-step explanation:
