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Svetlanka [38]
2 years ago
11

What is the measure of the angle?​

Mathematics
1 answer:
Sonja [21]2 years ago
3 0

Answer:

I think the Question of ans is 50°

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PLEASE HELP I NEED HELP !!!!!!!! The graph of a line passes through the two points (-2, 1) and (2, 1). What is the equation of t
MrRissso [65]

Answer:

y - 1 = 0

Step-by-step explanation:

We know that Equation of a line is given by,

y - y₁ / x - x₁ = y₂ - y₁ / x₂ - x₁

Let A(-2,1) and B(2,1)

x₁ = -2 ; x₂ = 2 ; y₁ = 1 ; y₂ = 1

Substituting the values,

y - 1 / x - (-2) = 1 - 1 / 2 - (-2)

y - 1 / x + 2 = 0

y - 1 = 0

7 0
3 years ago
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If 3 out of 10 mammalian cell cultures exposed to ultraviolet (UV) radiation developed chromosomal abnormalities while 9 out of
Zina [86]

Answer:

a) Observational Study

b) Risk in observational study

RR = 9/10/3/10 = 3.0

c) Relative risk when exposed to  a common NSAID is 3 out of 10 people

Step-by-step explanation:

A) This is observational study

b) The parameter determined here is the risk in observational study

RR = 9/10/3/10 = 3.0

c) Relative risk of mammalian cell to develop chromosomal abnormalities when exposed to  a common NSAID is 3 out of 10 people

8 0
3 years ago
What is the number that has the same value as l6l
Elodia [21]

Answer:6

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3 0
2 years ago
Which is the steepest? Explanation that includes the graph. (The graph is on the picture)
fomenos

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D

Step-by-step explanation:

3 0
3 years ago
Which of the following is a trinomial with a constant term.
Sunny_sXe [5.5K]
<h2>The "option d: y^5 + 13x + 12"​ is a trinomial with a constant term.</h2>

Step-by-step explanation:

To check options:

a: x + 4y

Here, the coefficient of x = 1 and the coefficient of y = 4

b: x^3

Here, the coefficient of x^3 = 1

c: x^4 + 3y^2 + 2y

Here, the coefficient of x^4  = 1, the coefficient of y^2 = 4 and the coefficient of y = 2

d: y^5 + 13x + 12​

Here, the coefficient of y^5   = 1, the coefficient of x = 13 and

constant term = 12

Thus, the "option d)  y^5 + 13x + 12"​ is a trinomial with a constant term.

6 0
3 years ago
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